如何将列表分为n个相等的部分，python

问题描述

给出( any )单词列表lst，我应该将其分为10个相等的部分.

Given (any) list of words lst I should divide it into 10 equal parts.

x = len(lst)/10

如何给这些零件赋予变量名?

how to give these parts variable names?

在输出中，我需要10个变量(part1, part2... part10)，其中的单词数为x.

In the output I need 10 variables (part1, part2... part10) with x number of words in it.

推荐答案

单行返回列表列表，并给出列表和块大小:

One-liner returning a list of lists, given a list and the chunk size:

>>> lol = lambda lst, sz: [lst[i:i+sz] for i in range(0, len(lst), sz)]

测试:

>>> x = range(20, 36)
>>> print x
[20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35]

>>> lol(x, 4)
[[20, 21, 22, 23],
 [24, 25, 26, 27],
 [28, 29, 30, 31],
 [32, 33, 34, 35]]

>>> lol(x, 7)
[[20, 21, 22, 23, 24, 25, 26],
 [27, 28, 29, 30, 31, 32, 33],
 [34, 35]]

更新:

好吧，在这种情况下，您可以尝试:

Well, in this case, you can try:

def slice_list(input, size):
    input_size = len(input)
    slice_size = input_size / size
    remain = input_size % size
    result = []
    iterator = iter(input)
    for i in range(size):
        result.append([])
        for j in range(slice_size):
            result[i].append(iterator.next())
        if remain:
            result[i].append(iterator.next())
            remain -= 1
    return result

我确定这可以改善，但是我感到很懒. :-)

I'm sure this can be improved but I'm feeling lazy. :-)

>>> slice_list(x, 7)
[[20, 21, 22], [23, 24, 25],
 [26, 27], [28, 29],
 [30, 31], [32, 33],
 [34, 35]]

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