本文介绍了ArrayList 的 ConcurrentModificationException的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下一段代码:
private String toString(List<DrugStrength> aDrugStrengthList) {
StringBuilder str = new StringBuilder();
for (DrugStrength aDrugStrength : aDrugStrengthList) {
if (!aDrugStrength.isValidDrugDescription()) {
aDrugStrengthList.remove(aDrugStrength);
}
}
str.append(aDrugStrengthList);
if (str.indexOf("]") != -1) {
str.insert(str.lastIndexOf("]"), "
" );
}
return str.toString();
}
当我尝试运行它时,我得到 ConcurrentModificationException
,谁能解释为什么会发生,即使代码在同一线程中运行?我怎样才能避免它?
When I try to run it, I get ConcurrentModificationException
, can anyone explain why it happens, even if the code is running in same thread? And how could I avoid it?
推荐答案
如果您使用for each"循环浏览列表,则无法从列表中删除.您可以使用 Iterator
.替换:
You can't remove from list if you're browsing it with "for each" loop. You can use Iterator
. Replace:
for (DrugStrength aDrugStrength : aDrugStrengthList) {
if (!aDrugStrength.isValidDrugDescription()) {
aDrugStrengthList.remove(aDrugStrength);
}
}
与:
for (Iterator<DrugStrength> it = aDrugStrengthList.iterator(); it.hasNext(); ) {
DrugStrength aDrugStrength = it.next();
if (!aDrugStrength.isValidDrugDescription()) {
it.remove();
}
}
这篇关于ArrayList 的 ConcurrentModificationException的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!