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问题描述

我很困惑.

我能够使用 LightOpenID 使openid登录工作正常.

I was able to make openid login kinda work using LightOpenID.

我所做的只是一个openid_identity,例如"https://www.google.com/accounts/o8/id?id=xxx".非常令人失望:我也希望获得电子邮件地址.

All I get doing that is just an openid_identity such as "https://www.google.com/accounts/o8/id?id=xxx". Pretty disappointing: I was expecting to get the email address too.

我需要登录(这就是openid的功能) ,以了解用户用于登录的Google帐户的电子邮件地址.

i.e. I need to login (that's what openid does) and to know the email address of the google account the user used to login.

有功能$openid->getAttributes(),但是我从中得到的只是一个空数组:我想Google除了提供openid_identity之外不会给我任何东西.

There is the function $openid->getAttributes() but all I get from that is just an empty array: I guess google isn't going to give me anything else than that openid_identity.

所以我我应该使用OAuth,对吗?我对此一无所知.我只发现了可怕而混乱的文档,要么假装解释了一切(而我是指一切),要么却无法解释< .

So I guess I'm supposed to use OAuth, right?I'm clueless about that.I've only found horrible and confused documentation, that either pretends to explain everything (and I do mean everything), or it fails explain anything at all.

是的,当然,正如我在Google上搜索时一样,我尝试查看有关该内容的以前的帖子.请再次阅读以上段落.

Yes, of course I've tried to look at the previous posts about that, just as I did search on google. Read again the above paragraph, please.

推荐答案

我刚刚发现了 LightOpenID ,我认为这很棒.通过example-gmail.php的以下修改,我设法获得了电子邮件地址,名字和首选语言:

I've just discovered LightOpenID and I think it's wonderful. I've managed to get the email address, the first and last name and the prefered language using the following modification of example-gmail.php:

<?php

require_once('openid.php');

if (empty($_GET['openid_mode']))
{
    if (isset($_GET['login']))
    {
        $openid = new LightOpenID();
        $openid->identity = 'https://www.google.com/accounts/o8/id';
        $openid->required = array('namePerson/first', 'namePerson/last', 'contact/email', 'pref/language');

        header('Location: ' . $openid->authUrl());
        //header('Location: ' . str_replace('&amp;', '&', $openid->authUrl()));
    }

    else
    {
        echo '<form action="?login" method="post">' . "\n";
        echo '<button>Login with Google</button>' . "\n";
        echo '</form>' . "\n";
    }
}

else if ($_GET['openid_mode'] == 'cancel')
{
    echo 'User has canceled authentication!';
}

else
{
    $openid = new LightOpenID();

    echo 'User ' . ($openid->validate() ? $_GET['openid_identity'] . ' has ' : 'has not ') . 'logged in.';

    echo '<pre>';
    print_r($openid->getAttributes());
    echo '</pre>';
}

?>

我更改了代码以使其更具可读性,即输出:

I changed the code to make it a little more readable, the output:

User https://www.google.com/accounts/o8/id?id=*** has logged in.

Array
(
    [namePerson/first] => Alix
    [contact/email] => ***@gmail.com
    [pref/language] => en
    [namePerson/last] => Axel
)

我仍然无法从Google获得邮政编码和其他邮政编码,但是我在 myOpenID.com 上取得了成功.

I still can't get the postal code and others from Google but I've had success with myOpenID.com.

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08-07 01:56