获取当前节点 xpath

问题描述

我需要获取我为其编写了 xsl 函数的当前节点的 xpath

I need to get the xpath of current node for which i have written an xsl function

<func:function name="fn:getXpath">
    <xsl:variable name="xpath">
        <xsl:for-each select="ancestor-or-self::*">
            <xsl:value-of select="concat($xpath, name())" />
            <xsl:if test="not(position()=last())">
                <xsl:value-of select="concat('/', $xpath)" />
            </xsl:if>
        </xsl:for-each>
    </xsl:variable>
    <func:result select="$xpath" />
</func:function>

但是当我运行这个时，我收到以下错误

But when I run this, I'm getting the following error

file:///D:/test.xsl; Line #165; Column #63; Variable accessed before it is bound!
file:///D:/test.xsl; Line #165; Column #63; java.lang.NullPointerException

我使用的是 xalan 2.7.0.请帮忙.

I'm using xalan 2.7.0. Please help.

推荐答案

您在变量本身的定义中使用了变量 $xpath:

You are using the variable $xpath inside the definition of the variable itself:

<func:function name="fn:getXpath">
    <xsl:variable name="xpath">
        <xsl:for-each select="ancestor-or-self::*">
            <xsl:value-of select="concat($xpath, name())" />   <-------
            <xsl:if test="not(position()=last())">
                <xsl:value-of select="concat('/', $xpath)" />  <-------
            </xsl:if>
        </xsl:for-each>
    </xsl:variable>
    <func:result select="$xpath" />
</func:function>

此时变量未知.

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