Java8生成器的自然数无限序列

问题描述

我为Java8 迭代器的自然数的无限序列（ Stream ）定义了自然 。

I defined natural for Infinite sequence (Stream) of Natural numbers with Java8 iterator.

IntStream natural = IntStream.iterate(0, i -> i + 1);

natural
 .limit(10)
 .forEach(System.out::println);

现在，我想用Java8 generator 。

Now, I want to define it with Java8 generator.

静态流生成（供应商）

最简单的方法是什么？谢谢。

What would be the simplest way? Thanks.

推荐答案

注意：@assylias使用 AtomicInteger设法用lambda做到了/ code>。他应该有接受的答案。

Note: @assylias managed to do it with a lambda using AtomicInteger. He should probably have the accepted answer.

我不确定你可以使用lambda（因为它是有状态的），但是使用普通的供应商这可以工作：

I'm not sure you can do that with a lambda (because it is stateful), but with a plain Supplier this would work:

IntSupplier generator = new IntSupplier() {
    int current = 0;

    public int getAsInt() {
        return current++;
    }
};

IntStream natural = IntStream.generate(generator);

然而，我非常喜欢您当前的解决方案，因为这是目的of iterate（int seed，IntUnaryOperator f）恕我直言：

However, I highly prefer your current solution, because this is the purpose of iterate(int seed, IntUnaryOperator f) IMHO:

IntStream natural = IntStream.iterate(0, i -> i + 1);

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