销售苹果股票（第1号中出）

问题描述

任何人可以帮助我与我的code，我有一个问题时，即时通讯销售我的苹果，
它减去所有的股票和放大器;有时，当我输入超过股票数量变为负

Can anybody help me with my code , i have a problem when im selling my apples,it subtract all of my stocks & sometimes the number goes negative when my input exceeds the stocks

int main(void){

int choice = 0;
int days = 1, i, buyApple;
int stocks[99] = {0};

for (;;){

    clrscr();
    printf("Day %d\n", days);

    printf("1. harvest\n");
    printf("2. View Stocks\n");
    printf("3. Sell\n");
    printf("\nchoice: ");

    scanf("%d", &choice);

    if (choice == 1){

        clrscr();
        printf("Input No. of Apple harvested: ");
        scanf("%d", &stocks[days]);
        days++;
    }
    if (choice == 2){

        clrscr();
        printf("Day    Stocks\n");

        for (i = 1; i < days; i++){

            printf("%2d     %4d\n", i, stocks[i]);      
    }
     getch();

    }
    if(choice == 3){

        printf("Input No. of Appple to be sold: ");
        scanf("%d", &buyApple);

        for (i = 0; i < buyApple; i++){
          stocks[i] = stocks[i] - buyApple;

    }
    if(stocks[i] > buyApple)

        printf("Out of Stocks!");

        getch();    
    }

}
}

期望输出：

例如我的股票是这样

  Day    Stocks
     1      100
     2       50
     3       50
     4      180
     5      200

如果我输入号苹果出售200

if i input No. apples to be sold is 200

我的股票会变成这个样子。

my stocks will become like this

Day    Stocks
  1        0
  2        0
  3        0
  4      180
  5      200

在1月1日退出

当我的投入超过了股票，它会说缺货了！，它不会继续减少我的股票

and when my Input exceeds the stocks it will say "Out of Stocks !" and it will not continue reduce my stocks

推荐答案

在问题的评论中第三个选择的问题，正确的code应该是这样的（它的C＃）：

The issue in third choice as in question comments ,the correct code should be like this (it's c#) :

if (choice == 3)
{

    printf("Input No. of Appple to be sold: ");
    scanf("%d", &buyApple);


    for (i = 1; i < sizeof(stocks); i++) //Looping on all stocks you have
    {
        if (buyApple <= stocks[i]) //if amount of apple less than stock apples ,then remove them from stock
        {
            stocks[i] = stocks[i] - buyApple;
            buyApple = 0;
            break;

        }
        else //if amount of apple is bigger than stock apples
        {
            if ((sizeof(stocks) - 1) == i){ //if it's the Last stock,then there is no apples in stock
                printf("Out of Stocks!");
            }
            else //take amount of apples from current stock 
            {
                buyApple = buyApple - stocks[i];
                stocks[i] = 0;
            }
        }

    }

    getch();
}

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