问题描述
我正在尝试使用Jackson 2中的@JsonIdentityInfo,如所述。
I am trying to use the @JsonIdentityInfo from Jackson 2 as described here.
出于测试目的,我创建了以下两个类:
For testing purposes I created the following two classes:
public class A
{
private B b;
// constructor(s) and getter/setter omitted
}
public class B
{
private A a;
// see above
}
当然,天真的方法很糟糕:
Of course, the naive approach failes:
@Test
public void testJacksonJr() throws Exception
{
A a = new A();
B b = new B(a);
a.setB(b);
String s = JSON.std.asString(a);// throws StackOverflowError
Assert.assertEquals("{\"@id\":1,\"b\":{\"@id\":2,\"a\":1}}", s);
}
添加 @JsonIdentityInfo(generator = ObjectIdGenerators.IntSequenceGenerator。 class,property =@ id)
到A类和/或B类也不起作用。
Adding @JsonIdentityInfo(generator=ObjectIdGenerators.IntSequenceGenerator.class, property="@id")
to class A and/or class B does not work either.
我希望我能序列化(以及后来反序列化) a
到这样的事情:(虽然不太确定JSON)
I was hoping that I could serialize (and later deserialize) a
to something like this: (not too sure about the JSON though)
{
"b": {
"@id": 1,
"a": {
"@id": 2,
"b": 1
}
}
}
我该怎么做?
推荐答案
看来有Jackson的一部分功能。 @JsonIdentityInfo
一定不能削减。
It seems jackson-jr has a subset of Jackson's features. @JsonIdentityInfo
must not have made the cut.
如果您可以使用完整的Jackson库,只需使用标准 ObjectMapper
使用您在问题中建议的 @JsonIdentityInfo
注释并序列化您的对象。例如
If you can use the full Jackson library, just use a standard ObjectMapper
with the @JsonIdentityInfo
annotation you suggested in your question and serialize your object. For example
@JsonIdentityInfo(generator=ObjectIdGenerators.IntSequenceGenerator.class, property="@id")
public class A {/* all that good stuff */}
@JsonIdentityInfo(generator=ObjectIdGenerators.IntSequenceGenerator.class, property="@id")
public class B {/* all that good stuff */}
然后
A a = new A();
B b = new B(a);
a.setB(b);
ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.writeValueAsString(a));
将生成
{
"@id": 1,
"b": {
"@id": 2,
"a": 1
}
}
其中嵌套的 a
通过 @id
引用根对象。
where the nested a
is referring to the root object by its @id
.
这篇关于如何在循环引用中使用@JsonIdentityInfo?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!