问题描述
我正在使用python和matplotlib来创建几个封闭的多边形。然后我需要用填充物填充它们,这可以通过set_hatch来完成。
I'm using python and matplotlib to create several closed polygons. I then need to fill them with a hatch, which can be done through set_hatch.
不幸的是我正在使用灰度图像,我需要比默认提供的更多的阴影 - 我更愿意提供一个可以平铺的位图(或一些类似的图像)而不是使用具有不同密度的这些阴影。
Unfortunately I am working with greyscale images, and I need more hatches than provided by default - I would prefer to provide a bitmap (or some similar image) which could be tiled instead of using these hatches with varying densities.
我对其他python库(pyglet,pygame,PIL等)开放,但是我希望解决方案是在python中。
I am open to other python libraries (pyglet, pygame, PIL, etc) however I would prefer the solution to be in python.
推荐答案
您可以继承 matplotlib.hatch.Shapes
并根据内部绘制的任何参考路径定义自定义填充单位平方[[-0.5,0 .5] x [-0.5,0.5]]。
You can subclass matplotlib.hatch.Shapes
and define a custom hatch based on any reference path drawn inside unit square [[-0.5, 0.5] x [-0.5, 0.5]].
暂定:
import numpy as np
import matplotlib.hatch
import matplotlib.pyplot as plt
from matplotlib.patches import Ellipse, Polygon
house_path = Polygon(
[[-0.3, -0.4], [0.3, -0.4], [0.3, 0.1], [0., 0.4], [-0.3, 0.1]],
closed=True, fill=False).get_path()
class CustomHatch(matplotlib.hatch.Shapes):
"""
Custom hatches defined by a path drawn inside [-0.5, 0.5] square.
Identifier 'c'.
"""
filled = True
size = 1.0
path = house_path
def __init__(self, hatch, density):
self.num_rows = (hatch.count('c')) * density
self.shape_vertices = self.path.vertices
self.shape_codes = self.path.codes
matplotlib.hatch.Shapes.__init__(self, hatch, density)
matplotlib.hatch._hatch_types.append(CustomHatch)
fig = plt.figure()
ax = fig.add_subplot(111)
ellipse = ax.add_patch(Ellipse((0.5, 0.5), 0.3, 0.5, fill=False))
ellipse.set_hatch('c')
ellipse.set_color('red')
plt.show()
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