升压:: shared_ptr的和std :: shared_ptr的同居

问题描述

我想用的boost ::登录在某些时候，但我不能传递的std :: shared_ptr的作为参数，因为编译器（VS2010）无法将其转换成的boost :: shared_ptr的。

I want to use boost::log at some point, but I cannot pass a std::shared_ptr as a parameter, because the compiler (VS2010) cannot convert it into a boost::shared_ptr.

我真的不喜欢的事实，他们是外星人彼此。

I don't really like the fact that they are aliens to one another.

有一个转换成另一个，以便它们不绊倒彼此安全和透明的方式？

Is there a safe and transparent way to convert one into the another, so as they don't stumble over each other?

我不认为这是重复的this问题的，各国都是一样的。

I don't think it is duplicate of this question that states both are the same.

推荐答案

您可以做到这一点是这样的：

You could do it like this:

template<typename T>
boost::shared_ptr<T> make_shared_ptr(std::shared_ptr<T>& ptr)
{
    return boost::shared_ptr<T>(ptr.get(), [ptr](T*) mutable {ptr.reset();});
}

template<typename T>
std::shared_ptr<T> make_shared_ptr(boost::shared_ptr<T>& ptr)
{
    return std::shared_ptr<T>(ptr.get(), [ptr](T*) mutable {ptr.reset();});
}

编辑：请注意，这不与向源PTR弱引用工作。所以，要小心那些！

Note that this does not work with weak references to the source ptr. So be careful with those!

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