问题描述
是否可以替换使用通配符找到的文本并将其替换为通配符?例如FindText:="(^13{2}*^13)", Forward:=True, MatchWildcards:=True,，然后将其替换为通配符，例如replacewith:="(^13{2}*^11)".有可能吗?
Is it possible to replace the text that was found using wildcard and replace it with wildcard also? for example FindText:="(^13{2}*^13)", Forward:=True, MatchWildcards:=True, then replace it with wildcard like this replacewith:="(^13{2}*^11)". Is it possible?
推荐答案
注释"中的整个讨论尚不清楚，但是我知道您只需要替换搜索词的一部分，而保留另一部分.是的，可以通过在搜索字词中定义表达式来实现.例如:
The entire discussion in Comments is unclear, but I understand that you need to replace only part of the search term, and retain another part. Yes, that's possible by defining expressions in the search term. For example:
查找:(^ 13 {2} *)^ 13"替换:\ 1 ^ 11
Find: "(^13{2}*)^13"Replace: \1^11
使用括号定义表达式.在查找"文本中可以有多个表达式.引用一个表达式，并让Word在使用反斜杠+索引的替换中使用它，其中index是查找"文本中表达式的编号(位置).在上面的示例中，从您的问题中提取了一个表达式，因此\ 1.
An expression is defined using parentheses. You can have multiple expressions in the "Find" text. Refer to an expression and have Word use it in the replacement using backslash+index, where index is the number (location) of the expression in the Find text. In the above example, taken from your question, there is one expression, so \1.
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