本文介绍了WPF:列表框和虚拟化的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
- 我如何知道我的列表是否已被虚拟化?
-
如何使此片段虚拟化?
- How do I know whether or not my list is being virtualized?
How do I make this snippet virtualized?
<ScrollViewer Grid.Column="1" Name="LogScroller">
<r:NoInheritanceContentControl>
<ListBox Background="Black" ItemsSource="{Binding Path=ActiveLog}" >
<ListBox.ItemTemplate>
<DataTemplate>
<Grid Background="Black">
<Grid.ColumnDefinitions>
<ColumnDefinition Width="200"></ColumnDefinition>
<ColumnDefinition Width="*"></ColumnDefinition>
</Grid.ColumnDefinitions>
<Grid.RowDefinitions>
<RowDefinition></RowDefinition>
<RowDefinition></RowDefinition>
</Grid.RowDefinitions>
<TextBlock Grid.Column="0" Grid.Row="0" Foreground="White">
<TextBlock >Date:</TextBlock>
<TextBlock Text="{Binding Path=LogDate}"/>
</TextBlock>
<TextBlock Grid.Column="1" Grid.Row="0" Foreground="White">
<TextBlock >Severity:</TextBlock>
<TextBlock Text="{Binding Path=Severity}"/>
</TextBlock>
<TextBlock Grid.Column="0" Grid.ColumnSpan="2" Grid.Row="1" Foreground="LightGray" Text="{Binding Path=Message}"></TextBlock>
</Grid>
</DataTemplate>
</ListBox.ItemTemplate>
<ListBox.Template>
<ControlTemplate>
<StackPanel Background="Black" IsItemsHost="True" >
</StackPanel>
</ControlTemplate>
</ListBox.Template>
</ListBox>
</r:NoInheritanceContentControl>
</ScrollViewer>
推荐答案
您的代码示例未虚拟化，因为您正在强制使用StackPanel.您必须使用VirtualizingStackPanel.
Your code sample does not virtualize because you are forcing the use of a StackPanel. You have to use a VirtualizingStackPanel.
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