线性功能

本文介绍了线性功能的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 我需要编写一个分段函数，可以将百分比从95到65并将其转换为gpa值。技巧是，95 = 4.0,94 = 3.9,93 = 3.8,92 = 3.7，并且每个百分点继续减少.1，直到它达到65 = 1.0。如果不手动输入大量的其他内容，我就会变得难以理解。 $（＃theButton ）.click（function（）{ var perc = $（＃perc）。val（）; var hardperc =（1 +（（perc-65）/ 10））; perc = parseFloat（perc）; 解决方案如果你想要简单的线性归一化，那么下面的函数应该可以做到。不是使用重复的逻辑或条件，你可以使用一些数学。 //可重用的线性规范化functionconst linearNormalize =（fromMin，fromMax，toMin，toMax）=> value => {//规范化输入值var pct =（value - fromMin）/（fromMax - fromMin）; var normalized = pct *（toMax - toMin）+ toMin; // Cap输出到min / max if（normalized> toMax）回到Max; if（normalized< toMin）返回Min; return normalized;} //包装函数与您的特定inputsConst gradeToGpa = linearNormalize（65,95,1.0,4.0）; console.log（gradeToGpa（78））; 使用 Scott Sauyet 咖喱功能建议： const linearNormalize =（fromMin，fromMax，toMin，toMax）=> value => {var pct =（value - fromMin）/（fromMax - fromMin）; var normalized = pct *（toMax - toMin）+ toMin; if（normalized> toMax）返回到; if（normalized< toMin）返回Min; return normalized;} const gradeToGpa = linearNormalize（65,95,1.0,4.0）; console.log（gradeToGpa（78））; I need to write a piecewise function that can take a percentage from 95 to 65 and convert that to a gpa value. The trick is, 95=4.0, 94=3.9, 93=3.8, 92=3.7, and that continues decreasing by .1 per percentage point until it hits 65=1.0. I'm becoming stumped how to code this without manually entering in a ton of else-ifs.$("#theButton").click(function() { var perc = $("#perc").val(); var hardperc = (1+((perc-65)/10)); perc = parseFloat(perc); 解决方案 If you want simple linear normalization then the following function should do the trick. Rather than use repeated logic or conditionals, you can just use some math.//Reusable Linear Normalization functionconst linearNormalize = (fromMin, fromMax, toMin, toMax) => value => { //Normalize the input value var pct = (value - fromMin) / (fromMax - fromMin); var normalized = pct * (toMax - toMin) + toMin; //Cap output to min/max if (normalized > toMax) return toMax; if (normalized < toMin) return toMin; return normalized;}//Wrapper function with your specific inputsconst gradeToGpa = linearNormalize(65, 95, 1.0, 4.0);console.log(gradeToGpa(78));With Scott Sauyet's curried functions suggestion:const linearNormalize = (fromMin, fromMax, toMin, toMax) => value => { var pct = (value - fromMin) / (fromMax - fromMin); var normalized = pct * (toMax - toMin) + toMin; if (normalized > toMax) return toMax; if (normalized < toMin) return toMin; return normalized;}const gradeToGpa = linearNormalize(65, 95, 1.0, 4.0);console.log(gradeToGpa(78)); 这篇关于线性功能的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！