XSLT 根据条件拆分 XML 文件

本文介绍了XSLT 根据条件拆分 XML 文件的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

首先，我对 xslt 的经验不够好.我需要帮助将 XML 拆分为基于 InoviceNo 的 2 个文件.如果 InvoiceNo = +"将它包含在前面的同级中，其中 InvoiceNo 等于一个数字.

First,I don't have good enough experience on xslt. I need help splitting the XML into 2 Files based on InoviceNo. If InvoiceNo = "+" include it in the preceding sibling where InvoiceNo equals a number.

源文件

<?xml version="1.0"?>
<ns:MT_CheckoutReport xmlns:ns="http://test.com/LE/ChannelAdvisor">
<row>
    <row>
        <InvoiceNo>547194</InvoiceNo>
        <CheckoutDate>8/02/2021 19:29</CheckoutDate>
        <TotalInvoiceAmt>159.99</TotalInvoiceAmt>
        <PymtType>Amazon</PymtType>
        <PymtID></PymtID>
        <PymtExp>0/0</PymtExp>
        <CVV></CVV>
    </row>
</row>
<row>
    <row>
        <InvoiceNo>547195</InvoiceNo>
        <CheckoutDate>8/02/2021 19:29</CheckoutDate>
        <TotalInvoiceAmt>219.98</TotalInvoiceAmt>
        <PymtType>Amazon</PymtType>
        <PymtID></PymtID>
        <PymtExp>0/0</PymtExp>
        <CVV></CVV>
    </row>
</row>
<row>
    <row>
        <InvoiceNo>+</InvoiceNo>
        <CheckoutDate></CheckoutDate>
        <TotalInvoiceAmt></TotalInvoiceAmt>
        <PymtType></PymtType>
        <PymtID></PymtID>
        <PymtExp></PymtExp>
        <CVV></CVV>
    </row>
</row>
</ns:MT_CheckoutReport>

所需的输出.文件 1

<?xml version="1.0"?>
<ns:MT_CheckoutReport xmlns:ns="http://test.com/LE/ChannelAdvisor">
<row>
    <row>
        <InvoiceNo>547194</InvoiceNo>
        <CheckoutDate>8/02/2021 19:29</CheckoutDate>
        <TotalInvoiceAmt>159.99</TotalInvoiceAmt>
        <PymtType>Amazon</PymtType>
        <PymtID></PymtID>
        <PymtExp>0/0</PymtExp>
        <CVV></CVV>
    </row>
</row>

文件 2. InvoiceNo = + 将其包含在具有前面同级的文件中，其中 InvoiceNo = 547195

File 2. InvoiceNo = + Include it in the file with preceeding sibling where the InvoiceNo = 547195

<?xml version="1.0"?>
<ns:MT_CheckoutReport xmlns:ns="http://test.com/LE/ChannelAdvisor">
<row>
    <row>
        <InvoiceNo>547195</InvoiceNo>
        <CheckoutDate>8/02/2021 19:29</CheckoutDate>
        <TotalInvoiceAmt>219.98</TotalInvoiceAmt>
        <PymtType>Amazon</PymtType>
        <PymtID></PymtID>
        <PymtExp>0/0</PymtExp>
        <CVV></CVV>
    </row>
</row>
<row>
    <row>
        <InvoiceNo>+</InvoiceNo>
        <CheckoutDate></CheckoutDate>
        <TotalInvoiceAmt></TotalInvoiceAmt>
        <PymtType></PymtType>
        <PymtID></PymtID>
        <PymtExp></PymtExp>
        <CVV></CVV>
    </row>
</row>

我的尝试

    <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template match="row">
  <xsl:for-each-group select="row/InvoiceNo" group-by="InvoiceNo">
    <xsl:result-document href="file_{current-grouping-key()}.xml">
       <some>
         <xsl:copy-of select="current-group()"/>
       </some>
    </xsl:result-document>
  </xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>

推荐答案

为什么不简单:

XSLT 2.0

<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns="http://test.com/LE/ChannelAdvisor">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/ns:MT_CheckoutReport">
    <xsl:for-each-group select="row" group-starting-with="row[row/InvoiceNo!='+']">
        <xsl:result-document href="file_{row/InvoiceNo}.xml">
            <ns:MT_CheckoutReport>
                <xsl:copy-of select="current-group()"/>
            </ns:MT_CheckoutReport>
        </xsl:result-document>
    </xsl:for-each-group>
</xsl:template>

</xsl:stylesheet>

这篇关于XSLT 根据条件拆分 XML 文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！