以纯文本形式获取 XML

问题描述

我有 Spring Rest API 的这个端点:

I have this endpoint for Spring Rest API:

@PostMapping(value = "/v1/", consumes = { MediaType.APPLICATION_XML_VALUE,
            MediaType.APPLICATION_JSON_VALUE }, produces = { MediaType.APPLICATION_XML_VALUE,
                    MediaType.APPLICATION_JSON_VALUE })
    public PaymentResponse handleMessage(@RequestBody PaymentTransaction transaction, HttpServletRequest request) throws Exception {

    // get here plain XML

}

XML 模型.

@XmlRootElement(name = "payment_transaction")
@XmlAccessorType(XmlAccessType.FIELD)
public class PaymentTransaction {
    public enum Response {
        failed_response, successful_response
    }

    @XmlElement(name = "transaction_type")
    public String transactionType;
    .........
}

如何以纯 XML 文本格式获取 XML 请求?

How I can get the XML request in plain XML text?

我也尝试过使用 Spring 拦截器:我试过这个代码:

I also tried with Spring interceptor:I tried this code:

@SpringBootApplication
@EntityScan("org.plugin.entity")
public class Application extends SpringBootServletInitializer implements WebMvcConfigurer {

    @Override
    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
        return application.sources(Application.class);
    }

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }
    ........

    @Bean
    public RestTemplate rsestTemplate() {
        List<ClientHttpRequestInterceptor> interceptors = new ArrayList<>();
        RestTemplate restTemplate = new RestTemplate(
                new BufferingClientHttpRequestFactory(new SimpleClientHttpRequestFactory()));
        restTemplate.setInterceptors(interceptors);
        return restTemplate;
    }
}

记录组件:

@Component
public class RestTemplateHeaderModifierInterceptor implements ClientHttpRequestInterceptor {

    @Override
    public ClientHttpResponse intercept(HttpRequest request, byte[] body, ClientHttpRequestExecution execution)
            throws IOException {

        StringBuilder sb = new StringBuilder();
        sb.append("[ ");
        for (byte b : body) {
            sb.append(String.format("0x%02X ", b));
        }
        sb.append("]");

        System.out.println("!!!!!!!!!!!!!!!");
        System.out.println(sb.toString());

        ClientHttpResponse response = execution.execute(request, body);

        InputStream inputStream = response.getBody();

        String result = IOUtils.toString(inputStream, StandardCharsets.UTF_8);

        System.out.println("!!!!!!!!!!!!!!!");
        System.out.println(result);

        return response;
    }
}

但是控制台没有打印任何内容.知道我错在哪里了吗?可能这个组件没有注册?

But nothing is printed into the console. Any idea where I'm wrong? Probably this component is not registered?

推荐答案

从 HttpServletRequest 获取它应该不会像下面这样容易，除非我遗漏了什么.我认为不需要使用拦截器等.

Shouldn't it be easy like below to get it from HttpServletRequest, unless I'm missing something. I don't think there is need to use interceptor etc.

@PostMapping(value = "/v1/", consumes = { MediaType.APPLICATION_XML_VALUE,
            MediaType.APPLICATION_JSON_VALUE }, produces = { MediaType.APPLICATION_XML_VALUE,
                    MediaType.APPLICATION_JSON_VALUE })
    public PaymentResponse handleMessage(HttpServletRequest request) throws Exception {

    String str, wholeXML = "";
    try {
        BufferedReader br = request.getReader();
        while ((str = br.readLine()) != null) {
            wholeXML += str;
        }
    System.out.println(wholeXML);
    //Here goes comment question, to convert it into PaymentTransaction
   JAXBContext jaxbContext = JAXBContext.newInstance(PaymentTransaction.class);
    Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();

    StringReader reader = new StringReader(wholeXML);
    PaymentTransaction paymentTransaction = (PaymentTransaction) unmarshaller.unmarshal(reader);
}

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