将 OpenStruct 深度转换为 JSON

问题描述

我有一个 OpenStruct，它与许多其他 OpenStructs 嵌套在一起.将它们全部深度转换为 JSON 的最佳方法是什么?

I have an OpenStruct that is nested with many other OpenStructs. What's the best way to deeply convert them all to JSON?

理想情况下:

x = OpenStruct.new
x.y = OpenStruct.new
x.y.z = OpenStruct.new
z = 'hello'

x.to_json
// {y: z: 'hello'}

现实

{ <OpenStruct= ....> }

推荐答案

没有默认的方法来完成这样的任务，因为内置的 #to_hash 返回哈希表示，但它不会深度转换值.

There is no default methods to accomplish such task because the built-in #to_hash returns the Hash representation but it doesn't deep converts the values.

如果一个值是一个 OpenStruct，它会原样返回并且不会被转换成一个 Hash.

If a value is an OpenStruct, it's returned as such and it's not converted into an Hash.

然而，解决这个问题并不复杂.您可以创建一个遍历 OpenStruct 实例中的每个键/值的方法(例如使用 each_pair)，如果值为一个 OpenStruct 并返回一个 Ruby 基本类型的 Hash.

However, this is not that complicated to solve. You can create a method that traverses each key/value in an OpenStruct instance (e.g. using each_pair), recursively descends into the nested OpenStructs if the value is an OpenStruct and returns an Hash of just Ruby basic types.

然后可以使用 .to_json 或 JSON.dump(hash) 轻松序列化此类 Hash.

Such Hash can then easily be serialized using either .to_json or JSON.dump(hash).

这是一个非常简单的例子

This is a very quick example

def openstruct_to_hash(object, hash = {})
  object.each_pair do |key, value|
    hash[key] = value.is_a?(OpenStruct) ? openstruct_to_hash(value) : value
  end
  hash
end

openstruct_to_hash(OpenStruct.new(foo: 1, bar: OpenStruct.new(baz: 2)))
# => {:foo=>1, :bar=>{:baz=>2}}

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