问题描述
在Windows系统上，备份代理创建的临时隐藏文件与原始文件的名称几乎相同，并且路径相同.这可能会干扰使用PHP scandir()的进程.
On a Windows system, a backup agent created temporary hidden files of nearly the same name as the original files, and in the same path. This was probably disturbing a process that used PHP scandir().
现在，我想知道Windows上具有隐藏标志集的文件是否被PHP scandir()排除.
Now I was wondering if files on Windows having the hidden flag set are excluded by PHP scandir().
有些文章介绍了Linux风格的隐藏文件，scandir()如何忽略以点开头的文件，但很少有有关Windows文件的信息.
There are some articles about the hidden files in Linux style, how scandir() should ignore files that start with a dot, but there is rarely no info about Windows files.
推荐答案
简短的测试表明，scandir()，glob()或其他都不会处理隐藏的标志.
A short test shows that neither scandir() nor glob() or others take care of the hidden flag.
这是实验和结果:
零件:
- Windows 7
- PHP 5.6.9(x86)
- Visual Studio 2012可再发行的x86
因此scandir()不会隐藏设置了隐藏标志的文件.
So scandir() does not hide files having the hidden flag set.
下一个问题是，是否可以配置功能更强大的PHP命令，例如glob().
Next question is, can more powerful PHP commands like glob() be configured.
首先，没有用于处理标志的参数:
Firstly, there is no parameter to deal with flags:
http://php.net/manual/de/function.glob.php
其次，加布里埃尔·卢拉斯基(Gabriel S. Luraschi)的这句话很有说服力:
Secondly, there is this telling comment of Gabriel S. Luraschi:
http://php.net/manual/de/function.glob .php#110510
他推荐exec('dir ... \A ...').但是在商业托管(如果它们在Windows上运行)上，将不允许这样做.
He recommends exec('dir ... \A ...'). But on commercial hostings (if they run on Windows), this will not be allowed.
请确保:使用Linux样式，并忽略以点开头的文件，例如:
To be sure: use the Linux style and ignore files that start with a dot, like here:
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