将叉（）在iOS应用中可能是由苹果公司的审查程序被拒绝？

问题描述

我正在写一个机制（在iOS应用）来检测设备是否通过检查通过执行叉（应用程序沙箱的完整性越狱）; 。有谁知道，如果在尝试此调用会侵犯App Store的指引？

I'm writing a mechanism (in an iOS app) to detect whether a device is jailbroken by checking for App sandbox's integrity by doing a fork();. Does anyone know if attempting this call would violate App Store guidelines?

推荐答案

fork（）的（等）不会让你拒绝;由该香草操作系统拒绝操作不能同时提交被再现。
我有一个使用fork（）和（）调用来检查越狱的环境和他们没有得到拒绝了这个在AppStore上的应用：）

fork() (and other) will not get you rejected; operations that are denied by the vanilla os cannot be reproduced while in submission.I have applications on the appstore that use fork() and system() calls to check for jailbreak environment and none of them got rejected for this :)

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