本文介绍了Swashbuckle MapType<类型>不适用于参数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 29岁程序员,3月因学历无情被辞! 我有一个将 ShortGuid 类作为参数的 API 端点,如下所示:I've got an API endpoint that takes a ShortGuid class as a parameter, like such:[HttpGet("api/endpoint")]public async Task<IActionResult> GetTablesAsync(ShortGuid id){}生成一个大摇大摆的定义:Generates a swagger definition of:"parameters":[ { "name":"guid", "in":"query", "required":false, "type":"string", "format":"uuid" }, { "name":"value", "in":"query", "required":false, "type":"string" }],我需要将该参数视为字符串,而不是 ShortGuid 对象.我已经有一个可以正常工作的类型的 JsonConverter,但是 Swashbuckle 不理解它,所以我的架构不正确(而且我的 swagger-js 客户端不起作用).我认为 MapType 会起作用,但这似乎只影响响应对象,因为架构仍将其视为 ShortGuid.I need to treat that parameter as a string, not a ShortGuid object. I already have a JsonConverter for the type that works fine, but Swashbuckle doesn't understand it so my schema is incorrect (and this my swagger-js client doesnt work). I thought MapType<> would work however that seems to only affect response objects as the schema still treats it as a ShortGuid.c.MapType<ShortGuid>(() => new Schema { Type = "string" });我需要一个 ISchemaFilter 来执行此操作吗?如果是这样,我该如何编写它(尝试了多次但没有成功)Will I require an ISchemaFilter to do this? And if so, how do I go about writing it (tried multiple attempts but no success)推荐答案为此,您必须为您的 ShortGuid 添加一个 TypeConverter.For this to work on the query string, you have to add a TypeConverter for your ShortGuid.这里有一些关于为什么它不起作用的信息:https://github.com/dotnet/aspnetcore/issues/4825Here is some information on why it does not work otherwise: https://github.com/dotnet/aspnetcore/issues/4825另外请注意,如果您使用 Nullable,您还需要添加 c.MapType.请参阅 https://github.com/domaindrivendev/Swashbuckle.AspNetCore/issues/1648 为此.Also note that if you use a Nullable<ShortGuid>, you will also need to add c.MapType<ShortGuid?>(...). See https://github.com/domaindrivendev/Swashbuckle.AspNetCore/issues/1648 for that. 这篇关于Swashbuckle MapType<类型>不适用于参数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 上岸,阿里云! 06-28 22:50