问题描述
我有以下代码:
<?php
$a = 1;
$b = 2;
echo "sum: " . $a + $b;
echo "sum: " . ($a + $b);
?>
执行代码时,我得到:
2
sum: 3
为什么在第一个回显中无法打印字符串"sum:"
?将加号放在括号中似乎很好.
Why does it fail to print the string "sum:"
in the first echo? It seems to be fine when the addition is enclosed in parentheses.
这种奇怪的行为在任何地方都有记录吗?
Is this weird behaviour anywhere documented?
推荐答案
两个运算符加法+
运算符和串联.
运算符都具有相同的运算符优先级,但是由于它们保持关联性,因此它们的评估如下:
Both operators the addition +
operator and the concatenation .
operator have the same operator precedence, but since they are left associative they get evaluated like the following:
echo (("sum:" . $a) + $b);
echo ("sum:" . ($a + $b));
因此,您的第一行首先进行连接,最后以:
So your first line does the concatenation first and ends up with:
"sum: 1" + 2
(现在,由于这是一个数字上下文,因此您的字符串被转换为整数,因此您最终得到0 + 2
,然后得到结果2
.)
(Now since this is a numeric context your string gets converted to an integer and thus you end up with 0 + 2
, which then gives you the result 2
.)
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