如何使用 winapi 的 SendInput 发送密钥?

问题描述

我正在尝试使用 winapi-rs 0.2.4 将本示例转换为 Rust 1.3.

I am trying to convert this example to Rust 1.3 with winapi-rs 0.2.4.

我有:

fn send_key_event(vk: u16, flags: u32) {
    let mut input = winapi::INPUT {
        type_: winapi::INPUT_KEYBOARD,
        union_: winapi::KEYBDINPUT {
            wVk: vk,
            wScan: 0,
            dwFlags: flags,
            time: 0,
            dwExtraInfo: 0,
        }
    };
    unsafe {
        user32::SendInput(1, &mut input, mem::size_of::<winapi::INPUT>() as i32);
    }
}

不编译:

error: mismatched types:
 expected `winapi::winuser::MOUSEINPUT`,
    found `winapi::winuser::KEYBDINPUT`
(expected struct `winapi::winuser::MOUSEINPUT`,
    found struct `winapi::winuser::KEYBDINPUT`) [E0308]

如何将击键发送到活动窗口?

Haw do I send keystrokes to the active window?

推荐答案

您使用的winapi-rs版本中winapi::INPUT的定义有误.今天似乎已修复(或昨天，取决于您所在的位置).

The definition of winapi::INPUT in the version of winapi-rs you use is incorrect. It appears to have been fixed today (or yesterday, depending on where you are).

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