本文介绍了如何从C#中的propertygrid控件中检索项目的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
使用以下代码绑定propertygrid.
Binding propertygrid with following code.
private void dgvDistribution_CellContentClick(object sender, DataGridViewCellEventArgs e)
{
Distribution di = new Distribution();
di.VoiceNo = dgvDistribution[1, dgvDistribution.CurrentRow.Index].Value.ToString();
di.Account_Name = dgvDistribution[2, dgvDistribution.CurrentRow.Index].Value.ToString();
di.DictatorName = dgvDistribution[6, dgvDistribution.CurrentRow.Index].Value.ToString();
di.Lastname = dgvDistribution[14, dgvDistribution.CurrentRow.Index].Value.ToString();
di.Firstname = dgvDistribution[15, dgvDistribution.CurrentRow.Index].Value.ToString();
di.Middlename = dgvDistribution[16, dgvDistribution.CurrentRow.Index].Value.ToString();
di.PatientID = dgvDistribution[22, dgvDistribution.CurrentRow.Index].Value.ToString();
di.MRNO = dgvDistribution[23, dgvDistribution.CurrentRow.Index].Value.ToString();
di.dateofadmission = dgvDistribution[33, dgvDistribution.CurrentRow.Index].Value.ToString();
di.Dateofservice = dgvDistribution[26, dgvDistribution.CurrentRow.Index].Value.ToString();
di.RPhysician = dgvDistribution[24, dgvDistribution.CurrentRow.Index].Value.ToString();
di.dateofbirth = dgvDistribution[25, dgvDistribution.CurrentRow.Index].Value.ToString();
di.dictateddatesdifferent = dgvDistribution[34, dgvDistribution.CurrentRow.Index].Value.ToString();
di.Remarks = dgvDistribution[21, dgvDistribution.CurrentRow.Index].Value.ToString();
di.ccphy = dgvDistribution[27, dgvDistribution.CurrentRow.Index].Value.ToString();
di.ccphyinvalid = dgvDistribution[28, dgvDistribution.CurrentRow.Index].Value.ToString();
di.worktype = dgvDistribution[8, dgvDistribution.CurrentRow.Index].Value.ToString();
propertyGrid1.SelectedObject = di;
}推荐答案
Distribution d = PropertyGrid1.SelectedObject as Distribution;
if (d != null)
{
Console.WriteLine(d.VoiceNo);
}
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