java.lang.NumberFormatException:对于输入字符串:

问题描述

运行此代码时:

JTextField ansTxt;
...
ansTxt = new JTextField(5);
String aString = ansTxt.getText();
int aInt = Integer.parseInt(aString);

为什么会出现此错误?

更新:

JTextField ansTxt;
ansTxt = new JTextField(5);

ansTxt.addKeyListener(new KeyAdapter() {
   public void keyReleased(KeyEvent e) {
    ansTxt = (JTextField) e.getSource();
    String aString = ansTxt.getText().trim();
    int aInt = Integer.parseInt(aString);
   }
}

推荐答案

JTextField构造函数实际上是 width 列数.从文档中:

The integer argument to the JTextField constructor is actually the width in number of columns. From the docs:

使用指定的列数构造一个新的空TextField.将创建一个默认模型，并将初始字符串设置为null.

Constructs a new empty TextField with the specified number of columns. A default model is created and the initial string is set to null.

通过构建它

ansTxt = new JTextField(5);

您基本上会得到一个空文本字段(比使用无参数构造函数构造的文本字段宽(宽)).如果要包含字符串"5"，请输入

you'll basically get an empty text-field (slightly wider than if you constructed it using no-argument constructor). If you want it to contain the string "5" you should write

ansTxt = new JTextField("5");

更新:IIRC，您将为keyDown获得一个事件，为keyTyped获得一个事件，并为keyUp获得一个事件.推测文本字段尚未在keyDown事件上更新.无论哪种方式，我建议您将Integer.parseInt封装在

Update:IIRC, you'll get one event for keyDown, one for keyTyped, and one for keyUp. Presumably the text-field has not yet been updated on the keyDown event.Either way I suggest that you encapsulate the Integer.parseInt in a

try { ... } catch (NumberFormatException e) { ... }

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