我该如何纠正这个？ | 我该如何纠正这个

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问题描述

我试图在这里运行一个简单的程序。预期的输出应该是：

I tried to run a simple programme here.The expected output should be :

Please enter customer'name
Kent Low
Please Enter Customer's Ic number
97xxxxxxxx
Please enter customer's phone number
0113838xxxx

相反，在我运行调试后它会显示如下：

Instead it show up like this after I run the debug:

Please enter customer'name
Kent Low
Please Enter Customer's Ic number
Kent Low
Please enter customer's phone number

我尝试过：

What I have tried:

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char name[20];
    int IC;
    int p_num;



    printf("Please enter customer's name:\n");
    gets(name);
    printf("Please enter customer's IC number:\n");
    scanf("%d",&IC);
    printf("please enter customer's phone number:\n");
    scanf("d",&p_num);



    return 0;
}

推荐答案

char buffer[20] = {0};
buffer[0] = IC[0];//set first
buffer[1] = IC[1];//set second
for( int i = 2; i < strlen(IC);i++ ) {
  buffer[i] = 'X';//set char X
}

描述

永远不要使用此功能。

DESCRIPTION
Never use this function.

，因为获取电话可能会收到缓冲区超支。

尝试

because gets calls may end up in buffer overruns.

Try

#include <stdio.h>
#include <stdlib.h>

#define SIZE 20
int main()
{
    char name[SIZE];
    int IC;
    int p_num;

    printf("Please enter customer's name:\n");
    if ( ! fgets(name, SIZE, stdin) )
      return -1; // TODO: better error handling
    // TODO: remove (if present) the trailing newline
    printf("Please enter customer's IC number:\n");
    if ( scanf("%d",&IC) != 1)
      return -1; // TODO: better error handling
    printf("please enter customer's phone number:\n");
    if ( scanf("%d",&p_num) != 1)
      return -1; // TODO: better error handling


    printf("Values entered name='%s', IC=%d, p_num=%d\n", name, IC, p_num);

    return 0;
}

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