如何向清单中的接收者发送自定义广播动作?

本文介绍了如何向清单中的接收者发送自定义广播动作?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

MyReceiver.java

public class MyReceiver extends BroadcastReceiver {
    @Override
    public void onReceive(final Context context, final Intent intent) {
        Log.i("MyReceiver", "MyAction received!");
    }
}

在AndroidManifest.xml中(在application标记下)

<receiver android:name=".MyReceiver">
    <intent-filter>
        <action android:name="MyAction" />
    </intent-filter>
</receiver>

MainActivity.Java

public class MainActivity extends AppCompatActivity {
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        sendBroadcast(new Intent("MyAction"));
    }
}

MyReceiver.onReceive方法永远不会触发.我错过了什么吗?

MyReceiver.onReceive method is never triggered.Did I miss something?

推荐答案

然后，您必须使用一个明确的Intent，用于标识接收方，例如:

Then you have to use an explicit Intent, one that identifies the receiver, such as:

sendBroadcast(new Intent(this, MyReceiver.class).setAction("MyAction"));

请参阅Android 8发行文档中的广播限制.

See Broacast limitations in Android 8 release docs.

这篇关于如何向清单中的接收者发送自定义广播动作?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！