本文介绍了HTTPGET是不工作的查询字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的工作获得通过查询字符串数据。我这样做有httppost但不是我特林开始使用HTTPGET。但我不能。
i am working to get data by query string . i have done with httppost but not i am tring to get using httpget . but i am unable.
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("key", "android developer"));
String k = "android developer";
URI uri = new URI("http://10.0.2.2:8080/r/r.php");
HttpClient httpclient = new DefaultHttpClient();
HttpGet httpget = new HttpGet(uri);
//httpget.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
is = entity.getContent();
请高手帮我
推荐答案
您可以通过两种方式做到这一点:
You can do this via 2 ways:
使用URI生成器:的
new Uri.Builder()
.scheme("http")
.authority("foo.com")
.path("someservlet")
.appendQueryParameter("param1", foo)
.appendQueryParameter("param2", bar)
.build();
创建URL字符串自己:的
String paramString = URLEncodedUtils.format(nameValuePairs, "utf-8");
uri = new Uri("http://10.0.2.2:8080/r/r.php?" + paramString);
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