问题描述
我的数据库有两列.一列是自动递增id(Primary Key)
列,另一列是'Sentence'
列.手动输入内容,然后我就可以插入该值.但是,当我尝试插入会给出错误消息的变量值时.我尝试了不同的方法. ('?') /( ? )/(?)
对我不起作用.
My database have two column. One column is auto increment id(Primary Key)
and other is 'Sentence'
column. Manually type something and I can insert that value. But when I'm trying insert variable value that gives error message. I tried different ways. ('?') /( ? )/(?)
Not work anything for me.
int s1=9;
String s2="Kasuni";
String sql = "INSERT INTO sentences (Sentence) VALUES ( ? )";
PreparedStatement pstmtJ = conn.prepareStatement(sql);
//pstmtJ.setInt(1, s1);
pstmtJ.setString(1,s2);
pstmtJ.executeUpdate(sql);
我没有插入的第一个值是自动递增值.我只是发表评论,并在上面的代码中显示出来.
1st value I didn't insert because of that is auto increment value. I just comment and that shows in my above code.
错误消息:
Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? )' at line 1
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
at java.lang.reflect.Constructor.newInstance(Unknown Source)
at com.mysql.jdbc.Util.handleNewInstance(Util.java:406)
at com.mysql.jdbc.Util.getInstance(Util.java:381)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1030)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3558)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3490)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1959)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2109)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2642)
at com.mysql.jdbc.StatementImpl.executeUpdate(StatementImpl.java:1647)
at com.mysql.jdbc.StatementImpl.executeUpdate(StatementImpl.java:1566)
at TestJsoup.main(TestJsoup.java:66)
在尝试以下代码时:
int s1=9;
String s2="Kasuni";
String sql = "INSERT INTO sentences (Sentence) VALUES ('?')";
PreparedStatement pstmtJ = conn.prepareStatement(sql);
//pstmtJ.setInt(1, s1);
pstmtJ.setString(1,s2);
pstmtJ.executeUpdate(sql);
这会显示以下错误消息:
That gives following error messages:
Exception in thread "main" java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0).
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1055)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:926)
at com.mysql.jdbc.PreparedStatement.checkBounds(PreparedStatement.java:3646)
at com.mysql.jdbc.PreparedStatement.setInternal(PreparedStatement.java:3630)
at com.mysql.jdbc.PreparedStatement.setString(PreparedStatement.java:4481)
at TestJsoup.main(TestJsoup.java:65)
推荐答案
pstmtJ.executeUpdate(sql);
→您正在发送原始SQL字符串,因为它正在调用 Statement.executeUpdate(String).
pstmtJ.executeUpdate(sql);
→ You're sending the original SQL string, since that is calling Statement.executeUpdate(String).
改为使用pstmtJ.executeUpdate();
( PreparedStatement.executeUpdate())来执行准备好的语句.
Use pstmtJ.executeUpdate();
instead (PreparedStatement.executeUpdate()) to execute the prepared statement.
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