从Python列表项中删除标点符号

问题描述

我有一个类似的列表

['hello', '...', 'h3.a', 'ds4,']

这应该变成

['hello', 'h3a', 'ds4']

，我只想删除标点符号，使字母和数字保持完整.标点符号是string.punctuation常量中的任何内容.我知道这很简单，但是我对python有点了解，所以...

and i want to remove only the punctuation leaving the letters and numbers intact.Punctuation is anything in the string.punctuation constant.I know that this is gunna be simple but im kinda noobie at python so...

谢谢，giodamelio

Thanks,giodamelio

推荐答案

假设您的初始列表存储在变量x中，则可以使用以下方法:

Assuming that your initial list is stored in a variable x, you can use this:

>>> x = [''.join(c for c in s if c not in string.punctuation) for s in x]
>>> print(x)
['hello', '', 'h3a', 'ds4']

要删除空字符串，请执行以下操作:

To remove the empty strings:

>>> x = [s for s in x if s]
>>> print(x)
['hello', 'h3a', 'ds4']

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