本文介绍了正则表达式；删除所有标点符号，除了的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有以下正则表达式可以在任何空格或标点符号上拆分.如何从 :punct: 中排除 1 个或多个标点符号?假设我想排除撇号和逗号.我知道我可以明确地使用 [此处的所有标点符号] 而不是 [[:punct:]] 但我希望有一种排除方法.
I have the following regex that splits on any space or punctuation. How can I exclude 1 or more punctuation characters from :punct:? Let's say I'd like to exclude apostrophes and commas. I know I could explicitly use [all punctuation marks in here] instead of [[:punct:]] but I'm hoping for an exclusion method.
X <- "I'm not that good at regex yet, but am getting better!"
strsplit(X, "[[:space:]]|(?=[[:punct:]])", perl=TRUE)
[1] "I" "'" "m" "not" "that" "good" "at" "regex" "yet"
[10] "," "" "but" "am" "getting" "better" "!"
推荐答案
我不清楚您希望结果是什么，但您可以使用否定类 喜欢这个答案.
It's not clear to me what you want the result to be, but you might be able to use negative classes like this answer.
R> strsplit(X, "[[:space:]]|(?=[^,'[:^punct:]])", perl=TRUE)[[1]]
[1] "I'm" "not" "that" "good" "at" "regex" "yet,"
[8] "but" "am" "getting" "better" "!"
这篇关于正则表达式；删除所有标点符号，除了的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！