本文介绍了编号的正则表达式捕获的最大数量是多少?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在维护一些通过串行无线电读取值并将它们解压为 Perl 数据结构的代码:
I'm maintaining some code that reads values over a serial radio and unpacks them into Perl data structures:
# Don't yell at me, I didn't write this
if ($command_string =~
/^.(.)(.).(..)(.)(..)(.)(....)(....)(....)(....)
(..)(..)(.)(.)(.)(.)(..)(..)(..)(..)(..)(..)(.)(.).......
(.)........(.)(.).*/sx) {
$config->{sequence} = hex(unpack('H2', $1));
$config->{radio_id} = hex(unpack('H2', $2));
...
$config->{radio_type} = hex(unpack('H2', $26));
$config->{radio_channel} = hex(unpack('H2', $27));
}
这个笨拙的捕获正则表达式让我想知道:Perl 中编号捕获变量的上限是多少?它一直到 $MAXINT
吗?
This unwieldy capturing regex made me wonder: what's the upper bound on numbered capture variables in Perl? Does it go all the way up to $MAXINT
?
推荐答案
这个脚本至少可以工作到 $N=5000000
.之后,它会耗尽内存.
This script works up to at least $N=5000000
. After that, it runs out of memory.
$N = $ARGV[0] || 5000;
$q = '(.)' x $N;
$regex = qr/$q/;
("x" x $N) =~ $regex;
print eval "\$$N";
这篇关于编号的正则表达式捕获的最大数量是多少?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!