问题描述
我想在运行程序时打开两种不同的形式.窗体分别命名为Form2和Form3.Form2可以正常运行，但Form3不能正常运行.我将 Application-> CreateForm(__ classid(TForm3)，& Form3); 放在我的项目cpp文件中，并将 Form3-> Show(); 放在我的Unit2中.cpp文件，但出现错误:模块'Project2.exe'中地址0047B2CE的访问冲突.读取地址00000384." 我在做什么错了?
I want to open two different forms when running my program. Forms are named Form2 and Form3. Form2 runs normally, but Form3 doesn't. I have put Application->CreateForm(__classid(TForm3), &Form3); on my project cpp file and Form3->Show(); in my Unit2.cpp file, but I get error: "Access violation at address 0047B2CE in module 'Project2.exe'. Read of address 00000384."What am I doing wrong?
推荐答案
虽然看不到您的实际代码，但是很难说，但是很可能您尚未创建 Form3 调用 Form3-> Show().您在接近0的内存地址处遇到错误，这很好地表明您可能正在访问NULL指针.
Without seeing your actual code, it is hard to say, but chances are that Form3 has simply not been created yet when you are calling Form3->Show(). You are getting an error at a memory address close to 0, which is a good indication that you are likely accessing a NULL pointer.
除非您希望在显示表单时获得更多控制权，否则无需调用 Show().您只需在设计时将其 Visible 属性设置为true，然后在调用 Application-> Run()启动消息循环时，让VCL为您显示它们即可.
You don't need to call Show() unless you want more control over WHEN the Forms are shown. You could simply set their Visible property to true at design-time and let the VCL show them for you when Application->Run() is called to start the message loop.
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