问题描述
我正在查看的文件称为examples.php,其中包含以下代码:
The file I'm viewing is called examples.php and contains the following code:
include (dirname(__FILE__) . "/adLDAP.php");
try {
$adldap = new adLDAP();
}
显示的错误为:
Fatal error: Class 'adLDAP' not found in /var/www/examples.php on line 14
第14行是:
$adldap = new adLDAP();
adLDAP.php与examples.php在同一文件夹中,并包含adLDAP类.
adLDAP.php is in the same folder as examples.php and contains the adLDAP class.
我弄乱了我的include语句吗?我尝试了其他格式的没有这样的文件或目录".感觉好像我缺少明显的东西.
Have I messed up my include statement? I get "no such file or directory" with the other formats I have tried. Feels like I'm missing something obvious.
adLDAP.php尽早实例化adLDAP类:
adLDAP.php instantiates the adLDAP class early on:
<?php
namespace adLDAP;
require_once(dirname(__FILE__) . '/collections/adLDAPCollection.php');
require_once(dirname(__FILE__) . '/classes/adLDAPGroups.php');
require_once(dirname(__FILE__) . '/classes/adLDAPUsers.php');
require_once(dirname(__FILE__) . '/classes/adLDAPFolders.php');
require_once(dirname(__FILE__) . '/classes/adLDAPUtils.php');
require_once(dirname(__FILE__) . '/classes/adLDAPContacts.php');
require_once(dirname(__FILE__) . '/classes/adLDAPExchange.php');
require_once(dirname(__FILE__) . '/classes/adLDAPComputers.php');
class adLDAP {
等
推荐答案
adLDAP
类定义在adLDAP
命名空间中.您需要告诉PHP此类在此名称空间中:
adLDAP
class definition is in adLDAP
namespace. You need to tell PHP that this class is in this namespace:
$adldap = new adLDAP\adLDAP();
您也可以使用use
关键字导入此类:
You can also import this class with use
keyword:
<?php
include (dirname(__FILE__) . "/adLDAP.php");
use adLDAP\adLDAP;
$adldap = new adLDAP;
这篇关于致命错误:找不到类"adLDAP"的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!