问题描述
我让用户提交电话号码.输入方式没有任何限制.我需要这个电话号码有两件事:区号(不包括前导0)和电话号码的其余部分.两者都没有非数字字符.
I am letting a user submit a phonenumber. There are no restrictions on how this is entered.What I need from this phone number are two things; The areacode (excluding the leading 0) and the rest of the phonenumber. Both without an non-digit chars.
用户可能输入的可能方案:
Possible scenarios the user might enter:
- 0707123456
- 0707-123456
- 0707-12 34 56
- 08-123 456 78
- 08-123 45 67
- 031-123 45 67
- 031-12 34 56
- 0480-12 34 56
- 0480-123 45
- +468 123 456 78
- +46(0)8 12 345 67 8
- 0707123456
- 0707-123456
- 0707-12 34 56
- 08-123 456 78
- 08-123 45 67
- 031-123 45 67
- 031-12 34 56
- 0480-12 34 56
- 0480-123 45
- +468 123 456 78
- +46 (0) 8 12 345 67 8
我想要得到的结果(两个NSStrings或int或其他):用户输入:0707123456
Var 1:70
Var 2:7123456
用户输入:+46(0)8 12 345 67 8
Var 1:8
Var 2:12345678
这些是区号:
Result I want to get (two NSStrings or int or whatever):User enters: 0707123456
Var 1: 70
Var 2: 7123456
User enters: +46 (0) 8 12 345 67 8
Var 1: 8
Var 2: 12345678
These are the area codes:
如何使用Objective-c做到这一点?
How can I do this with Objective-c?
推荐答案
我对Objective-c不太熟悉，但是答案应该能够解析所有提供的示例条目，并假设国家/地区代码为+46或没有国家/地区代码，并且支持列出的所有区号，因此会得到以下结果:
I am not very familiar with Objective-c, but an answer that should parse all of the provided example entries, assuming either a country code of +46 or no country code, and supporting all of the area codes listed, thus giving these results:
input (1) (2) (3)
--------------------- ------ ------ ---------------
0707123456 70 7123456
0707-123456 70 7-123456
0707-12 34 56 70 7-12 34 56
08-123 456 78 8 123 456 78
08-123 45 67 8 123 45 67
031-123 45 67 31 123 45 67
031-12 34 56 31 12 34 56
0480-12 34 56 480 12 34 56
0480-123 45 480 123 45
+468 123 456 78 +46 8 123 456 78
+46 (0) 8 12 345 67 8 +46 8 12 345 67 8
是这个表达式:
^[ -]*(\+46)?[ -]*[(0)]*[ -]*(70|730|76|271|322|174|472|371|589|961|960|570|583|226|624|915|531|652|932|662|921|278|243|33|142|661|456|693|914|912|431|571|295|586|552|653|942|534|271|381|471|171|246|16|413|223|346|515|23|590|122|585|157|241|943|684|258|528|645|241|493|371|158|498|525|555|591|390|514|551|672|970|693|26|31|511|563|975|643|582|220|175|35|696|644|297|922|928|224|684|225|291|42|513|301|503|290|671|506|650|495|36|663|345|591|611|451|42|491|415|413|253|247|971|621|647|36|916|923|480|505|454|294|586|455|54|150|554|320|980|494|435|580|977|612|44|550|640|226|19|300|227|303|221|430|925|418|584|247|474|302|478|692|510|581|13|642|372|651|657|240|920|46|950|523|913|157|40|280|953|496|159|501|433|530|142|553|250|141|392|524|563|499|587|223|930|11|176|918|512|481|155|380|622|297|454|250|304|479|491|643|155|978|435|911|973|623|175|934|457|459|472|924|682|248|224|26|414|416|511|910|222|142|294|500|240|620|952|8|951|290|152|433|526|670|695|60|565|220|418|585|680|325|687|246|564|533|253|225|382|293|270|121|456|504|502|293|60|477|304|417|691|560|16|486|345|325|140|410|520|156|954|292|506|522|613|321|90|18|143|393|156|123|281|512|340|383|125|940|492|933|151|495|498|981|976|322|521|935|370|490|21|470|411|571|532|690|647|573|474|941|120|476|251|929|431|144|485|295|19|173|660|291|63|292|173|926|927)[ -]*((?:\d[ -]*)+)
一个限制是区号必须是连续的数字(即070或70，但不能是0 7-0或0 7 0)
The one restriction is that the area code must be contiguous digits (i.e. 070 or 70, but not 0 7-0 or 0 7 0)
它将首先匹配国家/地区代码(如果存在)，并将其存储在反向引用1中，然后忽略单个零.然后，它将匹配一个区号并将其存储在反向引用2中.然后它将得到任意数量的数字(一个或多个)，并与破折号(-)和空格()混合并存储这些数字进入反向引用3
It will first match the country code, if it is present, and store it in back-reference 1, then ignore a single zero. It will then match one of the area codes and store it in back-reference 2. It will then get any number of digits (one or more), mixed with dashes (-) and spaces () and store those into back-reference 3
要在最后一部分得到一个实数(即从123 45-6-78获得12345678)，您将需要运行另一个查找并替换以消除空格和连字符/破折号.它既可以是传统的纯文本查找替换，也可以使用正则表达式，例如:[ -](用零长度的字符串替换)
To get a solid number in the last part (i.e. get 12345678 from 123 45-6-78), you will need to run another find and replace to get rid of spaces and hyphens/dashes. It can either be a either traditional text-only find-replace, or it could use a regex like: [ -] (replaced with a zero-length string)
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