本文介绍了XmlPullParser获取子节点的首选方式?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

获取XML字符串的子节点的首选方法是什么?似乎缺少在Android中使用XmlPullParser进行解析的良好示例.例如,如果我想解析这个:

What would be the preferred way of getting the child nodes of a XML string? There seems to be a lack of good examples of parsing with the XmlPullParser in android. For example if I would want to parse this:

<Point>
    <Id>81216</Id>
    <Name>Lund C</Name>
</Point>

我想出了一种方法来完成这项工作:

I came up with a way that does the job:

List<Point> points = new ArrayList<Point>();
String id = null
name = null;

while (eventType != XmlPullParser.END_DOCUMENT) {
    if (eventType == XmlPullParser.START_TAG && xpp.getName().equals("Id")) {
        try {
            id = xpp.nextText();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
    else if (eventType == XmlPullParser.START_TAG && xpp.getName().equals("Name")) {
    try {
        name = xpp.nextText();
    } catch (Exception e) {
        e.printStackTrace();
    }
    else if(eventType == XmlPullParser.END_TAG && xpp.getName().equals("Point")) {
        Point point = new Point(id, name);
        points.add(point);
    }

    try {
        eventType = xpp.next();
    } catch (exception e) {
        e.printStackTrace();
    }
}

for (Point p : points) {
    tv.append(p.getId() + " | " + p.getName() + "\n");
}

但这看起来真的很丑.有更好的方法吗?

But it seems really ugly. Is there a better way of doing this?

推荐答案

一种处理XML文本的更好方法就是在这里进行解释:

A better way to deal with texts in XML, in my opinion, would be like it is explained here:

http://androidcookbook.com/Recipe.seam?recipeId=2217

getText()不会生成异常,因为您位于XmlPullParser.TEXT区域内(因此可以确定是否有Text).

getText() wont generate Exceptions because you are inside an XmlPullParser.TEXT zone (so it is sure Text is there).

希望有帮助!

这篇关于XmlPullParser获取子节点的首选方式?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-18 08:26