本文介绍了如何在JTable中更改行的颜色的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想更改JTable中整行的颜色.
I want to change color of whole row in my JTable.
我定义了JTable:
I defined the JTable:
JTable table = new JTable(data, columnNames);
其中数据,columnNames是字符串表.
where data, columnNames are the String tables.
最常见的方法是编写自己的类:
The most common way to do this is to write own class:
public class StatusColumnCellRenderer extends DefaultTableCellRenderer {
@Override
public Component getTableCellRendererComponent(JTable table, Object value, boolean isSelected, boolean hasFocus, int row, int col) {
//Cells are by default rendered as a JLabel.
JLabel l = (JLabel) super.getTableCellRendererComponent(table, value, isSelected, hasFocus, row, col);
//Get the status for the current row.
l.setBackground(Color.GREEN);
//Return the JLabel which renders the cell.
return l;
}
}
并致电:
this.table.getColumnModel().getColumn(0).setCellRenderer(new StatusColumnCellRenderer());
但这是行不通的.我在做什么错了?
But it is doesn't work. What am I doing wrong?
推荐答案
您最初正确设置了TableCellRenderer
,但随后将其替换为以下代码:
You're setting the TableCellRenderer
correctly initially but then you're replacing it with this code:
for (int i = 0 ; i < table.getColumnCount(); i++)
table.getColumnModel().getColumn(i).setCellRenderer( centerRenderer );
对其进行更改,以使其将彩色单元格渲染器设置为正确的索引(并添加大括号(!)):
Change it so that it sets the colored cell renderer at the correct index (and add braces(!)):
for (int i = 0; i < table.getColumnCount(); i++) {
TableColumn column = table.getColumnModel().getColumn(i);
if (i == COLOR_COLUMN) { // COLOR_COLUMN = 1
column.setCellRenderer(new StatusColumnCellRenderer());
} else {
column.setCellRenderer(centerRenderer);
}
}
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