问题描述
说一个人有很多 House 和 House 有很多门。 （因此，门有一个 house_id ，而众议院有一个 person_id 领域）。我在Active Admin中有一个门列表，其中需要一个过滤器，该过滤器允许我选择一个人，并向我显示该人所有房屋中的所有门。
Say a Person has many House and House has many Door. (So Door has a house_id and House has a person_id field). I have a list of Doors in Active Admin, in which I want a filter that allows me to choose a person, and show me all doors in all of that person's houses.
ActiveAdmin.register Door do
filter :knob_color
filter :is_open
filter :has_window
filter :house_person # DOESN'T WORK
filter :house_person_name # DOESN'T WORK
Person 模型表具有一个 name 字段，因此ActiveAdmin应该能够选择该字段
The Person model table has a name field, so ActiveAdmin should be able to pick that up.
我该怎么做？
根据要求，我的情况在模型中更改。
As requested, my situation rephrased in models.
# id: integer
# name: string
class Person < ActiveRecord::Base
has_many :houses
end
# id: integer
# person_id: integer
class House < ActiveRecord::Base
belongs_to :person
has_many :doors
end
# id: integer
# house_id: integer
# knob_color: string
# is_open: boolean
# has_window: boolean
class Door < ActiveRecord::Base
belongs_to :house
end
推荐答案
您需要使用 has_one 门上注册人关联/ code>关系通过 house ，然后您可以直接添加过滤器。
You need to register a person association on Door using a has_one relation through house, and then you can add the filter directly.
class Door < ActiveRecord::Base
belongs_to :house
has_one :person, through: :house
end
ActiveAdmin.register Door do
filter :person
end
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