通过内部联接使用分组方式时得到错误的总和

问题描述

关于此问题()我有两个表 orders 和 order_items .我需要按天分组结果.但是我还需要每天从另一张表中获取 energy_used 的总和.当我尝试使用联接进行尝试时，我每天都会得到错误的 order_sum (它们没有被累加).不知道我在做什么错.

With reference to this question (How to get the sum in a joined table when using group by - getting wrong results) I have two tables orders and order_items. I need to group the results by days. But I also need to get the sum of energy_used for each day from another table. When I try that using a join, I get wrong order_sum for each day (they are not being summed up). Not sure what I am doing wrong.

我想每天得到

• 当天创建的所有订单的 order_items.energy_used 之和
• 当天创建的所有订单的 orders.order_sum 之和
• 与当天创建的最新 order 相对应的 created_at 和 order_sum

• the sum of order_items.energy_used for all orders created that day
• the sum of orders.order_sum for all orders created that day
• the created_at and order_sum that correspond to the latest order created on that day

这是我的 orders 表

+----+-----------+---------+---------------------+
| id | order_sum | user_id | created_at          |
+----+-----------+---------+---------------------+
| 1  | 25.13     | 7       | 2020-01-25 09:13:00 |
| 2  | 10.00     | 7       | 2020-01-25 15:23:00 |
| 3  | 14.00     | 5       | 2020-01-26 10:14:00 |
| 4  | 35.00     | 1       | 2020-01-27 11:13:00 |
+----+-----------+---------+---------------------+

这是我的 order_items 表

+----+----------+-------------+---------------------+
| id | order_id | energy_used | created_at          |
+----+----------+-------------+---------------------+
| 1  | 1        | 65          | 2020-01-25 09:13:00 |
| 2  | 1        | 12          | 2020-01-25 09:13:00 |
| 3  | 2        | 70          | 2020-01-26 10:14:00 |
| 4  | 2        | 5           | 2020-01-26 10:14:00 |
| 5  | 3        | 0           | 2020-01-27 11:13:00 |
+----+----------+-------------+---------------------+

这是我想要达到的预期结果

And this is the desired result that I am trying to achieve

+---------------+-----------------+-------------------+---------------------+----------------+
| date_of_month | total_order_sum | total_energy_used | last_order_date     | last_order_sum |
+---------------+-----------------+-------------------+---------------------+----------------+
| 2020-01-25    | 35.13           | 77                | 2020-01-25 09:13:00 | 25.13          |
| 2020-01-26    | 14.00           | 75                | 2020-01-26 10:14:00 | 14.00          |
| 2020-01-27    | 35.00           | 0                 | 2020-01-27 11:13:00 | 35.00          |
+---------------+-----------------+-------------------+---------------------+----------------+

这是我尝试过的查询，但结果不正确，order_sum没有正确计算.它显示与 last_order_sum

And here is the query that I have tried but I'm getting wrong results, the order_sum is not being calculated correctly. It is showing the same as last_order_sum

select 
    date(o.created_at) date_of_month,
    i.total_energy_used,
    o.created_at last_order_date,
    o.order_sum last_order_sum,
    sum(order_sum) as total_order_sum
from orders o
inner join (
    select date(o1.created_at) date_of_month, sum(i1.energy_used) total_energy_used
    from orders o1
    inner join order_items i1 on o1.id = i1.order_id
    group by date(o1.created_at)
) i on i.date_of_month = date(o.created_at)
where o.created_at = (
    select max(o1.created_at)
    from orders o1
    where date(o1.created_at) = date(o.created_at)
)

这是一个小提琴: https://dbfiddle.uk/?rdbms=mysql_5.6&fiddle=92b8cc2920ad9f7a7cd/a>

Here is a fiddle:https://dbfiddle.uk/?rdbms=mysql_5.6&fiddle=92b8cc2920ad9f7a7cdd56bded5a3bf2

推荐答案

始终将表之间的关系(在这种情况下为orders.id和order_items.order_id)连接在一起，然后进行分组.为了避免在加入时将多个order_sums的order_sums重复，请先按order_id将order_items分组.

Always join tables together on their relationships (in this case orders.id with order_items.order_id) and then group. to avoid duplicating order_sums for multiple order_items when joining, first group order_items by order_id.

select 
    date(o.created_at) date_of_month,
    sum(i.total_energy_used),
    max(o.created_at),
    sum(order_sum) as total_order_sum
from orders o
inner join (
    select order_id, sum(total_energy_used) total_energy_used
    from order_items i
    group by order_id
) i on o.id = i.order_id
group by date(o.created_at)

从现在开始，您可以再次对具有max(o.created_at)的订单进行联接，以获取最后一个订单的order_sum.故事的寓意:关注您的粒度.

from this point onwards you can do a join again on orders with max(o.created_at) to get the order_sum of the last order.moral of the story: keep an eye on your granularity.

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