Android的TimerTask的抛出的RuntimeException如果显示ProgressDialog在运行加（）

问题描述

我试图安排使用的TimerTask定时器。我希望在任务是使用ProgressDialog运行冻结UI。我使用的AsyncTask与TimerTask的达到预期的效果。但是，当我添加进度对话框code到TimerTask的Runnable接口，它抛出运行时异常。下面是code为TimerTask的，任何帮助将是AP preciated。先谢谢了。

公共类MyTimerTask扩展的TimerTask {
    上下文contxt;
    公共MyTimerTask（上下文CN）{
        contxt = CN;

 }
公共无效的run（）{
尝试{PD = ProgressDialog.show（contxt，搜索记录，请稍候...，真实，真实）; reqtype =GO;
 _getRecords =新InitTask（）;
 _getRecords.execute（contxt）;}赶上（例外五）{
Log.e（＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;错误执行MyAsyncTask：e.getMessage（），E）;
}
}
}
 

解决方案

这可能是因为你正试图使用​​一个线程nonGUI GUI功能。看一看http://developer.android.com/reference/android/app/Activity.html#runOnUiThread%28java.lang.Runnable%29一个可能的修复程序。

I am trying to schedule a timer using the timertask. I want to freeze the UI when the task is running using the ProgressDialog. I am using AsyncTask with TimerTask to achieve the desired results. But when I add Progress Dialog code to TimerTask Runnable, it throws Runtime Exception. Below is the code for TimerTask, Any help would be appreciated. Thanks in advance.

public class MyTimerTask extends TimerTask { Context contxt; public MyTimerTask(Context cn){ contxt=cn;

}
public void run() { 
try { 

pd=ProgressDialog.show(contxt, "Searching For Records", "Please wait...", true, true);

 reqtype="GO";
 _getRecords=new InitTask();
 _getRecords.execute(contxt);

} catch (Exception e) { 
Log.e(">>>>>>>>>>>> Error executing MyAsyncTask: ", e.getMessage(), e); 
} 
} 
} 

解决方案

That probably happens because you are attempting to use GUI features in a nonGUI thread. Have a look at http://developer.android.com/reference/android/app/Activity.html#runOnUiThread%28java.lang.Runnable%29 for a possible fix.

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