问题描述
我有一个控制GPIB电源的CAPL测试节点。该CAPL生成一个每3 ms修改一次的信号。我的CAPL看起来像这样:
I have a CAPL test node that controls a GPIB power supply. This CAPL generates a signal that is modified each 3 ms. My CAPL looks like this:
...
testcase wavGenerator()
{
GPIBWrite(myDevice, "VOLT", voltValue);
testwaitfortimeout(3);
...
}
问题是此testwaitfortimeout()函数会在测试报告中生成注释,并且由于我为每个测试用例使用此功能2000/3000次,因此我得出了巨大的测试报告。
The problem is that this testwaitfortimeout() function generates a comment in the test report, and since i use this function 2000/3000 times for each testcase, I end with a enormous test report.
我尝试实现一个函数来生成延迟,就像waitfortimeout()一样,
I have tried implementing a function to generate a "delay" like waitfortimeout() does, like this:
void delay(int ms)
{
float refTime;
refTime = timeNowFloat();
while(timeNowFloat() < (refTime + ms*100))
{
/* Wait to reach expected time*/
}
}
但这会使CANoe崩溃。我已经使用setTimer()函数尝试过类似的操作,但是问题是相同的。我怎么能产生这种延迟?
but this crashes CANoe. I have tried something like this with setTimer() functions but the problem is the same. How can I generate this delay?
推荐答案
我找到了一种使用计时器,EnvVar和函数来处理此延迟的方法。 testWaitForEnvVar()
I found a way to deal with this, using a timer, an EnvVar and the function testWaitForEnvVar()
on timer tDelay
{
@EnvDelayFunct = 1;
}
void delay(int ms)
{
int a;
write("Wait for %i ms", ms);
setTimer(tDelay, ms);
a = testWaitForEnvVar(EnvDelayFunct, 0);
@EnvDelayFunct = 0;
}
这篇关于除了testwaitfortimeout()外,CAPL中的延迟函数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!