本文介绍了公用表表达式的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

用ctss作为



(选择COUNT(st.id)作为计数,

lcty.name作为地点,

spec.speciality as Specality,

0 as Doctor,

0 as unknownspecordoc,

0 unknownLocality





来自ST_Search_Data作为st



内部加入SpecialityMaster作为st.specalityId的规格= spec.id



内连接lcty.id = st.localityId上的lcty位置



其中

(st.specalityId为NOT NULL且st.specalityId!=''且st.localityId不为NULL且st.localityId!='')



group BY spec.speciality,lcty.name)







select ct。 *,ROW_NUMBER()OVER(通过ct.counts DESC订购)作为行

来自ctss作为ct

其中(ct.row> = 1)和(ct.row< ; = 5)





嗨朋友,


在上面的代码中,我怀疑如何获得行号?

在我的任务中,我必须得到行号以进行分页从sql本身..但在上面的查询中,使用group by函数来获取没有特殊性和局部性的数量..如何在按函数使用时获取行?...在​​最后一行,其中(ct.row> = 1)和(ct.row< = 5)没有这一行我的查询正确执行,但是在最后一行,我得到错误无效的列名行。

with ctss as
(
(select COUNT(st.id) as counts,
lcty.name as Locality,
spec.speciality as Specality,
0 as Doctor,
0 as unknownspecordoc ,
0 unknownLocality


from ST_Search_Data as st

inner join SpecialityMaster as spec on st.specalityId=spec.id

inner join Locality as lcty on lcty.id=st.localityId

where
(st.specalityId is NOT NULL and st.specalityId !='' and st.localityId is not NULL AND st.localityId !='')

group BY spec.speciality , lcty.name)

)

select ct.*,ROW_NUMBER() OVER(ORDER BY ct.counts DESC) as row
from ctss as ct
where (ct.row>=1)and (ct.row<=5)


hi friends,

in this above code , i have doubt about how to get row number ?
in my task, i have to get row number for pagination from sql itself.. but in above query ,there used group by function for getting no.of counts of specality and locality.. how can i get row when used group by function?.. at last line , where (ct.row>=1)and (ct.row<=5) without this line my query excuted correctly, but with the last line , am getting error invalid column name row.

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09-21 08:47