本文介绍了添加到 FlatList 的正确方法的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

四处寻找将项目添加到平面列表的正确或最佳方式

Searching around for the correct, or best way to add an item to a flatlist

我的第一个方法是简单地向状态添加一个项目..所以我尝试了这个:

my first approach was to simple add an item to the state.. so I tried this:

var NewObject = {};
NewObject.Name = "New Object";
this.setState({
    Data: [...this.state.Data, ...[NewObject]]
});

但是,这样做似乎会导致列表中的所有内容都被读取,并且我会遇到各种关键错误.

However, doing this causes everything in the list to be readded it seems, and i get all sorts of key errors.

是 this.state.Data.push(NewObject);该方法?这似乎不允许重新加载

is this.state.Data.push(NewObject); the approach? that dosen't seem to allow a reload

任何帮助都是巨大的!

推荐答案

可以使用

this.setState({Data: [...this.state.Data, newObject]})

并且在 flatlist 中有一个extraData"道具.使用它来通知 flatlist 其数据源的任何更改.

And there is an 'extraData' prop in flatlist. Use it to notify flatlist about any changes in its datasource.

<FlatList
...
extraData={this.state.Data}
...
>

this.state.Data.push(NewObject) 直接改变状态,永远不要那样做.

this.state.Data.push(NewObject) mutates the state directly, never do that.

P.s 您也可以将 FlatList 的父组件设置为 PureComponent 以获得更好的性能.

P.s You can also set parent component of FlatList as PureComponent for better performance.

这篇关于添加到 FlatList 的正确方法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

10-15 05:46