问题描述
我正在开发创建线程的代码，但没有扩展线程类或实现runnable接口，即通过匿名内部类..
I was developing the code of creating a thread but without extending the thread class or implementing the runnable interface , that is through anonymous inner classes ..
public class Mythread3 {
public static void main(String... a) {
Thread th = new Thread() {
public synchronized void run() {
for (int i = 0; i < 20; i++) {
try {
Thread.sleep(1000);
System.out.print(i + "\n" + "..");
} catch (Exception e) {
e.printStackTrace();
}
}
}
};
th.start();
Thread y = new Thread();
y.start();
}
}
现在请告诉我，我可以创建吗子线程也采用相同的方法.. !!我试过的是......
Now please advise me can I create child threads also with the same approach..!! what I have tried is that...
public class Mythread3 {
public static void main(String... a) {
Thread th = new Thread() {
public synchronized void run() {
for (int i = 0; i < 20; i++) {
try {
Thread.sleep(1000);
System.out.print(i + "\n" + "..");
} catch (Exception e) {
e.printStackTrace();
}
}
}
};
Thread th1 = new Thread() {
public synchronized void run() {
for (int i = 0; i < 20; i++) {
try {
Thread.sleep(1000);
System.out.print(i + "\n" + "..");
} catch (Exception e) {
e.printStackTrace();
}
}
}
};
th.start();
try {
th.join();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
th1.start();
}
}
但有两个run（）其中的方法，我认为这不实用..请指教..！
But there are two run() methods in it, I think this not practical..please advise..!
推荐答案
Runnable run = new Runnable() {
public void run() {
try {
for (int i = 0; i < 20; i++) {
Thread.sleep(1000);
System.out.print(i + "\n" + "..");
}
} catch (InterruptedException e) {
System.out.println(" interrupted");
}
}
};
new Thread(run).start();
new Thread(run).start();
在开始第二个之前不要等待一个完成，或者你有三个线程在一个是永远在运行（在这种情况下，额外的线程毫无意义）
Don't wait for one to finish before starting the second or you have three threads where on one is ever running (in which case the additional threads were pointless)
BTW：你的synchronized没有做任何有用的事情，但它可能导致线程无法正常工作。
BTW: Your synchronized isn't doing anything useful but it could cause the Thread to function incorrectly.
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