选择性nvidia #pragma optionNV(全部展开)

问题描述

我正在使用nvidia的unroll loops指令，但是还没有找到一种有选择地打开它的方法.

I'm playing around with nvidia's unroll loops directive, but haven't seen a way to turn it on selectively.

让我说我有这个...

Lets say I have this...

void testUnroll()
{
    #pragma optionNV(unroll all)
    for (...)
        ...
}

void testNoUnroll()
{
    for (...)
        ...
}

在这里，我假设两个循环最终都被展开.为了阻止这种情况，我认为解决方案将涉及在我想要影响的块之后重置指令，例如:

Here, I'm assuming both loops end up being unrolled. To stop this I think the solution will involve resetting the directive after the block I want affected, for example:

    #pragma optionNV(unroll all)
    for (...)
        ...
    #pragma optionNV(unroll default) //??

但是我不知道将展开行为重置为初始/默认设置的关键字. 这怎么办?如果有人还能指出一些有关NVIDIA编译器指令的官方文档，那就更好了.

However I don't know the keyword to reset the unroll behaviour to the initial/default setting. How can this be done? If anyone could also point to some official docs for nvidia's compiler directives that'd be even better.

当前，似乎只使用了程序中找到的最后一个#pragma optionNV(unroll *)指令(例如，在最后一行中抛出一个指令，它将覆盖上面的所有内容).

Currently, it seems only the last #pragma optionNV(unroll *) directive found in the program is used (eg throw one in the last line and it overrides everything above it).

推荐答案

根据此帖子在NVidia论坛上，之后没有关键字会将其设置为默认行为:

According to this post on the NVidia forums, having no keyword afterwards will set it to default behavior:

如果#pragma展开后未指定任何编号，则循环的跳变计数为常数时将完全展开，否则根本不会展开.

If no number is specified after #pragma unroll, the loop is completely unrolled if its trip count is constant, otherwise it is not unrolled at all.

我不确定它是否可以在GLSL上运行，但是您可以尝试:

I'm not sure if it works on GLSL, but you can maybe try:

#pragma optionNV(unroll)

如果有人尝试过，请告诉我们是否可行！

If anyone tries this, let us know if it works!

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