如何从阿尔杜伊诺的Xbee发送数据，并从C＃收到

问题描述

我有一个Arduino的XBee ，我有一个Sparkfun的XBee USB探险家。我想在我的C＃程序发送来自Ardunio的XBee数据（温度传感器）和接收它。

I have an Arduino XBee shield and I have a Sparkfun XBee USB explorer. I would like to send data (temperature sensor) that comes from the Ardunio XBee and receive it in my C# programme.

现在，让我们说，我想送45，100到我的C＃程序。

For now, let's say I want to send 45, 100 to my C# programme.

我没有收到来自的XBee屏蔽任何数据。我失去了与code什么？

I don't receive any data that comes from the XBee shield. Am I missing anything with the code?

下面code是Arduino的盾牌的XBee发件人：

The below code is the sender from the Arduino XBee shield:

SoftwareSerial mySerial(4,5);
void setup()
{
    mySerial.begin(9600);
}


void loop()
{
    if (mySerial.available() > 0)
    {
        mySerial.write(45);
        mySerial.write(',');
        mySerial.write(100);
        mySerial.write('\n');
    }
}

接收器code在C＃中的USB的XBee探险：

Receiver code for the USB XBee explorer in C#:

SerialPort port = new SerialPort();

public Form1()
{
    try
        {
            port.PortName = "COM8";
            port.BaudRate = 9600;
            port.DataBits = 8;
            port.Parity = Parity.None;
            port.StopBits = StopBits.One;
            port.Open();
            Console.WriteLine("Opened");
        }
        catch(Exception ex)
        {
            Console.WriteLine("Sorry! " + ex);
        }

        // Handler for receiving data
        port.DataReceived += serialPort1_DataReceived;
    }

    private void serialPort1_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
    {
        if (port.IsOpen == true)
        {
            string RxString = port.ReadLine();
            Console.WriteLine(RxString);
        }
    }

本的XBee配置：

The XBee configuration:

• 一的XBee是：协调AT模式 - 连接到USB Sparkfun浏览器


• 另外的XBee是：路由器AT模式 - 连接到Arduino的盾牌

由于tomlogic回答我的问题在堆栈溢出问题的 的XBee同时双向通信（发送器和接收器） 的。

As tomlogic answered my question in Stack Overflow question XBee two-way communication (sender and receiver) at the same time.

推荐答案

我得到了它的工作。这个问题是由我的空隙环（）方法。该mySerial应该像

I got it working. The problem was from my void loop() method. The mySerial should be like

mySerial.println(temperature);

• 但是，你必须检查mySerial RX，TX引脚，他们是正确的



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