本文介绍了图中的第K阶邻居-Python NetworkX的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个有向图,在这里我想有效地找到一个节点的所有K阶邻居的列表.将第K阶邻居定义为从正好在 K个跃点中的有关节点可以到达的所有节点.

I have a directed graph in which I want to efficiently find a list of all K-th order neighbors of a node. K-th order neighbors are defined as all nodes which can be reached from the node in question in exactly K hops.

我查看了networkx,唯一相关的功能是neighbors.但是,这仅返回顺序1的邻居.对于更高的阶数,我们需要迭代确定完整的集合.我相信应该有一种更有效的方法来访问networkx中的第K个邻居.

I looked at networkx and the only function relevant was neighbors. However, this just returns the order 1 neighbors. For higher order, we need to iterate to determine the full set. I believe there should be a more efficient way of accessing K-th order neighbors in networkx.

有没有一种功能可以有效地返回第K阶邻居,而无需增量构建集合?

Is there a function which efficiently returns the K-th order neighbors, without incrementally building the set?

如果Python中存在其他可能在这里有用的图形库,请务必提及这些.

In case there exist other graph libraries in Python which might be useful here, please do mention those.

推荐答案

您可以使用:nx.single_source_shortest_path_length(G, node, cutoff=K)

其中G是您的图形对象.

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09-14 14:35