问题描述
为什么在代码的指定位置会收到ConcurrentModificationException?我无法弄清楚自己在做什么错... removeMin()
方法正用于在列表pq
中定位最小值,将其删除并返回其值
Why do I get a ConcurrentModificationException at the specified location in my code? I cannot figure out what I am doing wrong... The removeMin()
method is being used to locate the min in the list pq
, remove it, and return its value
import java.util.Iterator;
import java.util.LinkedList;
public class test1 {
static LinkedList<Integer> list = new LinkedList<Integer>();
public static void main(String[] args) {
list.add(10);
list.add(4);
list.add(12);
list.add(3);
list.add(7);
System.out.println(removeMin());
}
public static Integer removeMin() {
LinkedList<Integer> pq = new LinkedList<Integer>();
Iterator<Integer> itPQ = pq.iterator();
// Put contents of list into pq
for (int i = 0; i < list.size(); i++) {
pq.add(list.removeFirst());
}
int min = Integer.MAX_VALUE;
int pos = 0;
int remPos = 0;
while (itPQ.hasNext()) {
Integer element = itPQ.next(); // I get ConcurrentModificationException here
if (element < min) {
min = element;
remPos = pos;
}
pos++;
}
pq.remove(remPos);
return remPos;
}
}
推荐答案
修改了从其获得的Collection后,不应认为Iterator可用. (对于java.util.concurrent.*集合类,放宽了此限制.)
An Iterator should not be considered usable once the Collection from which it was obtained is modified. (This restriction is relaxed for java.util.concurrent.* collection classes.)
您首先要获得pq
的迭代器,然后修改pq
.修改pq
后,迭代器itPQ
不再有效,因此当您尝试使用它时,会收到ConcurrentModificationException.
You are first obtaining an Iterator for pq
, then modifying pq
. Once you modify pq
, the Iterator itPQ
is no longer valid, so when you try to use it, you get a ConcurrentModificationException.
一种解决方案是将Iterator<Integer> itPQ = pq.iterator();
移到while
循环之前.更好的方法是完全不使用Iterator:
One solution is to move Iterator<Integer> itPQ = pq.iterator();
to right before the while
loop. A better approach is to do away with the explicit use of Iterator altogether:
for (Integer element : pq) {
从技术上讲,for-each循环在内部使用Iterator,因此,无论哪种方式,该循环仅在您不尝试在循环内修改pq
时才有效.
Technically, the for-each loop uses an Iterator internally, so either way, this loop would only be valid as long as you don’t try to modify pq
inside the loop.
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