问题描述
有两个具有一对多关系的数据对象类"A"和"B".我想从父数据对象和子数据对象中获取包含列的数据.如何在Silverstripe的ORM或SQL查询中实现这一点.
there are two dataobject classes "A" and "B" having one-to-many relationship. I want to get data containing columns from both parent and child dataobject. How to achieve this in Silverstripe 's ORM or SQL Query.
示例:数据对象"A"具有两个事件,第一个事件包含一个日期信息(开始和结束日期).第二个事件包含两个日期信息(开始和结束日期).
Example: Dataobject "A" has two events and first event contain one date info(start and end date). Second event contains two dates info (start and end date).
我想查询数据库以获取包含来自"A"和"B"的列的信息,结果应显示3行.一个来自"A",两个来自"B".
I want to query database to get information containing columns from both "A" and "B" and it should shows 3 row as result. one from "A" and two from "B".
我正在使用Silverstripe 2.4.电影可以显示多个日期.电影数据对象与MovieDate数据对象具有一对多关系.我想从Movie中获取所有列,并重复与它关联的MovieDate的每个记录.这意味着如果电影有两个日期,那么我想获得两个记录
I am using Silverstripe 2.4. A Movie Can have multiple dates to show. Movie dataobject has one-to-many relationship with MovieDate dataobject. I want to get all columns from Movie repeating each record of MovieDate associated with it. That means if movie has two dates, then I want to get two records
Title Desc StartDate EndDate
----- ---- --------- -------
Matrix AAA 2012-09-20 2012-09-20
Matrix AAA 2012-09-29 2012-09-29
以下是出于您的考虑而编写的代码
Here is code for your kind consideration
<?php
class Movie extends DataObject
{
public static $db = array(
'Title' => 'Varchar',
'Desc' => 'Text',
);
public static $defaults = array(
'RedirectionType' => 'Internal',
);
public static $has_one = array(
'Image' => 'Image',
'Parent' => 'Page',
"LinkTo" => "SiteTree"
);
public static $has_many = array(
'MovieDates' => 'MovieDate'
);
static $summary_fields = array(
'Title' => 'Movie Title',
'Desc' => 'Movie Description'
);
function getRequirementsForPopup() {
Requirements::customCSS("
.iframe_wrap {
top: 35%;
}
");
}
public function getCMSFields()
{
$fields = new FieldSet(new TabSet('Root', $tab1 = new Tab('Main')));
$fields->addFieldsToTab('Root.Main', new TextField('Title', 'Movie Title'));
$fields->addFieldsToTab('Root.Main', new TextareaField('Desc', 'Movie Description'));
$tablefield = new DataObjectManager(
$this,
'MovieDates',
'MovieDate',
array('MovieStartDate' => 'Movie Start', 'MovieEndDate' => 'Movie End')
);
$tablefield->setPopupWidth(900);
$tablefield->setAddTitle("Movie Date/Time");
$fields->addFieldsToTab('Root.Main', $tablefield);
$fields->addFieldsToTab('Root.Main', new LiteralField("Space", "</br></br></br></br></br>") );
return $fields;
}
}
<?php
class MovieDate extends DataObject{
static $db = array(
'MovieStartDate' => 'Datetime',
'MovieEndDate' => 'Datetime',
);
static $has_one = array(
'Movie' => 'Movie'
);
function getCMSFields(){
$fields = new FieldSet();
$movieStartDate = new DateField('MovieStartDate', 'Movie Start');
$movieStartDate->setConfig('showcalendar', true);
$fields->push($movieStartDate);
$movieEndDate = new DateField('MovieEndDate', 'Movie End');
$movieEndDate->setConfig('showcalendar', true);
$fields->push($movieEndDate);
$space = new LiteralField("Space", "</br></br></br></br></br>");
$fields->push($space);
return $fields;
}
}
我认为
推荐答案
您追求的是左联接".不幸的是,silverstripe无法使用内置的ORM查询来检索已联接表上的数据(请参见 http://doc.silverstripe.org/framework/en/2.4/topics/datamodel#joining )
what you're after is a 'left join', i think.unfortunately, silverstripe has no means of retrieving data on a joined table using the built-in ORM queries (see http://doc.silverstripe.org/framework/en/2.4/topics/datamodel#joining)
所以您需要在此处进行简单的sql查询:
so you need to go with a plain sql query here:
$query = "
SELECT `Movie`.*, `MovieDate`.*
FROM `Movie`
LEFT JOIN `MovieDate` ON `Movie`.`ID` = `MovieDate`.`MovieID`
ORDER BY `Movie`.`Title`
";
$records = DB::query($query);
您现在可以使用foreach
遍历$records
:
foreach($records as $record) {
print_r($record);
}
另请参阅此论坛主题以获取更多信息: http://www.silverstripe.org/general-questions/show/12745
also see this forum thread for additional information:http://www.silverstripe.org/general-questions/show/12745
这篇关于[Silverstripe 2.4]:如何从一对多关系中获取包含列的记录?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!