迭代 T 恤变体的递归函数

问题描述

限时删除！！

按照这个问题我需要把它放在一个函数中(可能是递归的)，以便我传入数组变体，它返回一个包含所有变体的数组.

Following this question I need to put it in a function (maybe recursive) so that I pass in the array variants and it returns a single array with all the variants.

我有一个包含不同 T 恤变体的数组，如下所示:

I have an array with the different t-shirt variants like this:

颜色:黑色、红色、蓝色

Color: Black, Red, Blue

尺码:L、M、XL

...

变体可能不同、更多尺寸、更少颜色或新变体，如组织变体.

The variants may differ, more sizes, les colors, or new variants like tissue variants.

我需要一个函数来返回一个包含所有迭代变体的数组，如下所示:

I need a function that returns an array with all the iterated variants like this:

0 颜色=>黑色尺寸=>L

0 Color=>Black Size=>L

1 色=>黑色尺寸=>M

1 Color=>Black Size=>M

2 色=>黑色 XL 码

2 Color=>Black Size XL

3 色=>红色尺寸=>L

3 Color=>Red Size=>L

4 色=>红色尺寸=>M

4 Color=>Red Size=>M

...

我无法绕过构建这个最终数组.任何帮助表示赞赏！

I can't get around building this final array. Any help is appreciated!

推荐答案

您正在寻找 数学归纳法.要回答您的第一个问题，您需要像这样混合搭配以满足您的需求:

You're looking for Mathematical induction. To answer your first question, you'll need something like this, mix and match to suite your needs:

function induction($arrays, $i = 0)
{
    if( ! isset($arrays[$i]))
    {
        return [];
    }
    if($i == count($arrays) - 1)
    {
        return $arrays[$i];
    }

    $temporaryCombination = induction($arrays, $i + 1);

    $result = [];

    foreach ($arrays[$i] as $value)
    {
        foreach ($temporaryCombination as $combination)
        {
            $result[] = is_array($combination)
                ? array_merge([$value], $combination) : [
                    $value,
                    $combination,
                ];
        }
    }

    return $result;
}

var_dump(induction([$color,$size,$material]));

巧合的是，通过回答你的第一个，我也回答了这个问题，上面的功能需要稍微调整一下.

Coincidently, or not, by answering your first, I've answer this question too, the above function needs just a little tweaking.

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