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问题描述

例如,我有一个阶乘程序,它需要保存非常大的整数,其长度可能超过 50 位.C++ 中的绝对最大原始数据类型是 unsigned long long int,最大值 18446744073709551615 只有 20 位长.这是 C++ 限制的链接:http://www.cplusplus.com/reference/climits/

For example I have a factorial program that needs to save really huge integers that can be 50+ digits long. The absolute maximum primitive data type in C++ is unsigned long long int with a maximum value 18446744073709551615 which is only 20 digits long. Here's the link to the limits of C++: http://www.cplusplus.com/reference/climits/

如何将大于某个变量的数字存储在某种变量中?

How do I store numbers that are larger than that in a variable of some sort?

推荐答案

如果你已经有了 boost 依赖(现在很多人都有),你可以使用 boost 多精度库.事实上,它已经有一个 阶乘程序,可以支持高达 128 位的输出,但进一步扩展它非常简单.

If you already have a boost dependency (which many people these days do), you can use the boost multi-precision library. In fact, it already has an example of a factorial program that can support output up to 128 bits, though extending it further is pretty trivial.

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07-25 21:06