使用Java流合并一对`int`数组

问题描述

此页面显示了如何将两者结合Integer对象的数组转换为Object对象的数组.

This page shows how to combine two arrays of Integer objects into an array of Object objects.

Integer[] firstArray = new Integer[] { 10 , 20 , 30 , 40 };
Integer[] secondArray = new Integer[] { 50 , 60 , 70 , 80 };
Object[] merged = 
        Stream
        .of( firstArray , secondArray )
        .flatMap( Stream :: of )
        .toArray()
;

➥有没有一种方法可以使用Java流来连接一对原始int值而不是对象的数组?

➥ Is there a way to use Java streams to concatenate a pair of arrays of primitive int values rather than objects?

int[] a = { 10 , 20 , 30 , 40 };
int[] b = { 50 , 60 , 70 , 80 };
int[] merged = … ?

我意识到使用Java流可能不是最有效的方法.但是我对基元和Java流的相互作用感到好奇.

I realize using Java streams may not be the most efficient way to go. But I am curious about the interplay of primitives and Java streams.

我知道 IntStream ，但看不到如何将其用于此目的.

I am aware of IntStream but cannot see how to use it for this purpose.

推荐答案

IntStream.concat

将每个数组转换为IntStream.然后调用 IntStream.concat 进行组合.

IntStream.concat

Transform each array into an IntStream. Then call IntStream.concat to combine.

最后，通过调用 IntStream::toArray .

Lastly, generate an array of int by calling IntStream::toArray.

int[] a = { 10 , 20 , 30 , 40 };
int[] b = { 50 , 60 , 70 , 80 };

int[] merged = IntStream.concat(IntStream.of(a), IntStream.of(b)).toArray();

System.out.println(Arrays.toString(merged));

请参见此在IdeOne.com上实时运行的代码.

输出:

[10, 20, 30, 40, 50, 60, 70, 80]

提示:要对结果进行排序，请调用 .sorted() 在.toArray()之前.如在IdeOne.com上运行.

Tip: To sort the results, call .sorted() before the .toArray(). As seen running on IdeOne.com.

这篇关于使用Java流合并一对`int`数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！