是否可以使用结构化数据查看人员?

问题描述

我查看了以人为中心的数据.

I have review data centered around people.

我想用结构化数据来代表这些评论.

I would like to represent these reviews with structured data.

类似这样的东西:( 从这里 )

Something like this: (from here)

这是我尝试的方法:(这是Google图书示例的变体这里)

This is what I tried: (It's a variation of the Google's Book example here)

<div itemscope itemtype="http://schema.org/Person">
  <h2>
    <span itemprop="honorificPrefix">Dr</span>
    <span itemprop="name">Joe Smith</span>
  </h2>
  <h3 itemprop="jobTitle">Doctor</h3>
  <div itemprop="description">Extra super Doctor</div>
  <div itemprop="aggregateRating" itemscope itemtype="http://schema.org/AggregateRating">
    <div>Doctor rating:
      <span itemprop="ratingValue">88</span> out of 
      <span itemprop="bestRating">100</span> with
      <span itemprop="ratingCount">20</span> ratings
    </div>
  </div>
</div>

现在，当我在 Google的测试工具中测试此代码时，我得到错误:

Now when I test this code in Google's testing tool, I get the error:

那么这是否意味着没有办法对具有结构化数据的人进行评分?

So does this mean that there is there no way to rate people with structured data?

推荐答案

仅 aggregateRating属性为CreativeWork/Offer/Organization/Place/Product定义，但没有为Person定义.

The aggregateRating property is only defined for CreativeWork/Offer/Organization/Place/Product, but not for Person.

替代品:

• AggregateRating 定义了 itemReviewed属性，该属性期望以Thing作为值，因此可以与Person一起使用:

• AggregateRating defines the itemReviewed property, which expects a Thing as value, so it can be used with Person:

AggregateRating→itemReviewed→Person

您可能还想考虑是否真的是在这里获得评分的人，而不是该人提供的东西(即像体检这样的服务):

You might also want to consider if it’s really the person that gets rated here, and not something that this person offers (i.e., a service like a medical examination):

Person→ makesOffer →Offer
Offer→ aggregateRating →AggregateRating

Person → makesOffer → Offer
Offer → aggregateRating → AggregateRating

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